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GMAT Prep?? (Rates) Need Help....Pract 2

Expert replies
by dferm » Wed May 14, 2008 6:36 am
Working alone at its own constant rate, a machine seals k cartons in 8 hours, and working alone at its own constant rate, a second machine seals k cartons in 4 hours. If the two machines, each working at its own constant rate and for the same period of time, together sealed a certain number of cartons, what percent of the cartons were sealed by the machine working at the faster rate?

A. 25%
B. 33 1/3%
C. 50%
D. 66 2/3%
E. 75%

Please Help...
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Source: — Problem Solving |

by aatech » Wed May 14, 2008 6:50 am
Machine 1 => 8 hours k cartons. So, in 1 hour it will seal k/8 cartons

Similarly machine 2 will seal k/4 cartons in 1 hour

Together, they will seal (k/8)+(k/4) = 3k/8 cartons in 1 hour

so % carton sealed by machine 2 (faster as it seal same no of cartons in lesser time)
= ((k/4)*100)/(3k/8) = 66 2/3%

What's the OA?
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by dferm » Wed May 14, 2008 6:57 am
ur correct.. but can you show me how u arrived @ 66 2/3% mathematically..break it down without the faces in it...

Please...

Thanks...
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by aatech » Wed May 14, 2008 7:07 am
Looks like "8)" is getting converted into faces.. lets see if this helps

Machine 1 => 8 hours k cartons. So, in 1 hour it will seal k/8 cartons

Similarly machine 2 will seal k/4 cartons in 1 hour

Together, they will seal [k/8]+[k/4] = 3k/8 cartons in 1 hour

so % carton sealed by machine 2 [faster as it seal same no of cartons in lesser time]
= [[k/4]*100]/[3k/8] = 66 2/3%
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