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## gmat prep question

This topic has 4 member replies
yvonne12 Master | Next Rank: 500 Posts
Joined
07 Feb 2007
Posted:
144 messages

#### gmat prep question

Sun Mar 04, 2007 12:23 pm
when a certain tree was first planted, it was 4 feet tall and the height of the tree increased by a constnt amount each year for the next 6 years. At the end of the 6th year the tree was 1/5 taller than it was at the end of the 4the year. By how many feet did the height fo the tree increase each year?

yvonne12 Master | Next Rank: 500 Posts
Joined
07 Feb 2007
Posted:
144 messages
Mon Mar 05, 2007 5:00 pm
thanks for taking the time. I appreciate it.

ssiva Junior | Next Rank: 30 Posts
Joined
13 Feb 2007
Posted:
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Mon Mar 05, 2007 10:51 am
At the end of the 6th year the tree was 1/5 taller than it was at the end of the 4the year.

So height at end of 6th year is greater then height at end of 4th year. ( Note the word "than" in the problem )

height at end of 6th year = height at end of 4th year + height at end of 4th year * (1/5)
4 + 6x = 4 + 4x + (4+4x)*1/5
4 + 6x = ( 4 + 4x ) * 6/5
x = 2/3

"

4+6x = (4+4x)*1/5 indicates that height at 6th year is less then height after 4 yrs; which cannot be true because height increases at a constant rate of x / year.

Last edited by ssiva on Tue Mar 06, 2007 1:39 pm; edited 1 time in total

jayhawk2001 Community Manager
Joined
28 Jan 2007
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Sun Mar 04, 2007 6:09 pm
Lets assume the tree grew by x feet each year (i.e. the constant rate).
At the end of the 6th year, the tree would be 4 + 6x. Similarly at the
end of the 4th year, it would be 4 + 4x.

Hence 4 + 6x = (4 + 4x)*6/5

or x = 2/3

yvonne12 Master | Next Rank: 500 Posts
Joined
07 Feb 2007
Posted:
144 messages
Mon Mar 05, 2007 8:22 am
where did you get 6/5??? its 1/5

thats the only thing that Im stuck on. please explain

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