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GMAT prep question
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parallel_chase
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The questions says lx-yl > lx-zl
Until unless we know the exact value or signs (+ or -) of x and z or x and y we cannot answer this question.
Statement I.
xyz<0
x could be on the left of number line
y could be on the left of number line
z could be on the left of number line
or x could be positive, y could be positive and z negative
Therefore insufficient.
Statement II.
xy<0
x could be positive, y could be negative or vice versa.
it does not tell us anything about z
Therefore insufficient.
Combining Statement I & II
xy<0 & xyz<0
x is positive y negative and z positive.
x negative y positive and z negative.
Insufficient.
Hence E.
Until unless we know the exact value or signs (+ or -) of x and z or x and y we cannot answer this question.
Statement I.
xyz<0
x could be on the left of number line
y could be on the left of number line
z could be on the left of number line
or x could be positive, y could be positive and z negative
Therefore insufficient.
Statement II.
xy<0
x could be positive, y could be negative or vice versa.
it does not tell us anything about z
Therefore insufficient.
Combining Statement I & II
xy<0 & xyz<0
x is positive y negative and z positive.
x negative y positive and z negative.
Insufficient.
Hence E.
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ricky
- Master | Next Rank: 500 Posts
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IMO E
This is best done if drawn on a number line..
(i)xyz<0
=> either x, y or z is negative...NOT SUFFICIENT
(ii)xy<0
=> either x or y is negative...It doesnt tell which one is negative.So NOT SUFFIECIENT.
Taking 1 and 2 we can c z is positive for sure. But still we dont know which one of x and y is negative.If x is negative then y and z would be positive and since xz >xy, z would be in between x and y.
But if y is negative then x would be in between y and z and still xz > xy.
So its inconclusive.Hence E
This is best done if drawn on a number line..
(i)xyz<0
=> either x, y or z is negative...NOT SUFFICIENT
(ii)xy<0
=> either x or y is negative...It doesnt tell which one is negative.So NOT SUFFIECIENT.
Taking 1 and 2 we can c z is positive for sure. But still we dont know which one of x and y is negative.If x is negative then y and z would be positive and since xz >xy, z would be in between x and y.
But if y is negative then x would be in between y and z and still xz > xy.
So its inconclusive.Hence E
