Alternatively, you can do 2-variable inequality problems graphically. Look at the first inequality:
x - y > -2, or rearranging:
y < x + 2
This inequality represents a region in the co-ordinate plane. The line
y = x + 2
is the boundary between the regions
y < x + 2 and
y > x + 2
You can draw that line, work out that when y < x + 2, the points must be below the line, and see all of the possible values for (x, y). We can do the same for the second equation, and thereby find the region where both inequalities must be true (they will be true for all points below the line y = x +2 which are above the line y = 0.5x + 3, and these points are only in the first quadrant). It's easier to see if you draw the picture.
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