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value of S when passenger is maximum

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value of S when passenger is maximum

by alivapriyada » Tue Sep 14, 2010 1:40 pm
The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1
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by goyalsau » Tue Sep 14, 2010 1:54 pm
alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1
Excellent question, I think answer is E
but will be pleased if somebody can please explain a quick way to solve it, i just put the values of S in the equation and looked for the biggest value of P but i am not sure that this is the right way to approach a problem like this,
quant whims are welcomed with some explanation......
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by klmehta03 » Tue Sep 14, 2010 6:32 pm
agree the answer is E
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by diebeatsthegmat » Tue Sep 14, 2010 7:11 pm
alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1
to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct
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by alivapriyada » Tue Sep 14, 2010 11:25 pm
diebeatsthegmat wrote:
alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1
to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct
OA is C not E
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by lokesh r » Wed Sep 15, 2010 3:11 am
alivapriyada wrote:
diebeatsthegmat wrote:
alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1
to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct
OA is C not E
Are u sure the answer is C.

Because when s=4 , p =32
when s=1; p= -2(1-4)2+32= 12+32=44

I guess answer must be E.
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by alivapriyada » Wed Sep 15, 2010 3:17 am
lokesh r wrote:
alivapriyada wrote:
diebeatsthegmat wrote:
alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1
to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct
OA is C not E
Are u sure the answer is C.

Because when s=4 , p =32
when s=1; p= -2(1-4)2+32= 12+32=44

I guess answer must be E.
yes m sure ,answer is C
this was the explanation provided in the MGMAT

The bus will carry its greatest passenger load when P is at its maximum value. If P = -2(S - 4)2 + 32, the maximum value of P is 32 because (S - 4)2 will never be negative, so the expression -2(S - 4)2 will never be positive. The maximum value for P will occur when -2(S - 4)2 = 0, i.e. when S = 4.

The correct answer is C.
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by goyalsau » Wed Sep 15, 2010 3:45 am
alivapriyada wrote:
yes m sure ,answer is C
this was the explanation provided in the MGMAT

The bus will carry its greatest passenger load when P is at its maximum value. If P = -2(S - 4)2 + 32, the maximum value of P is 32 because (S - 4)2 will never be negative, so the expression -2(S - 4)2 will never be positive. The maximum value for P will occur when -2(S - 4)2 = 0, i.e. when S = 4.

The correct answer is C.
it makes sense how s be negative..
experts comment please........
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by selango » Wed Sep 15, 2010 8:13 am
First I got confused seeing the equation.

I think its (s-4)^2

P = -2(S - 4)^2 + 32

When u sub other values we need to add 32 with one negative value which ll decrease P.

Only S=4 adds 32 with 0 and gives P=32 which is high.

Pick C
--Anand--
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by lokesh r » Wed Sep 15, 2010 12:44 pm
I think Selango corrected the equation very well.

It should be P = -2(S - 4)^2 + 32, in this case without any doubt the answer option is C.

Hi alivapriyada, i request you to pls check the question again

and if P = -2(S - 4)2 + 32 is what equation actuall is, as stated by question s is no of stops, so s has to be postivie integer

s=1,2,3,4.....

if s=1,p=44
if s=2,p=40
if s=3,p=36
if s=4,p=32 and so on..
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by [email protected] » Wed Sep 15, 2010 8:13 pm
Agreed. Folks, request you to post the questions with the right terminology. It helps save time :)
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by kushal.adhia » Wed Oct 27, 2010 8:01 am
Hi guys

sorry to start on this question all over again, but can someone please explain the solution to me step by step?
I really had no idea on how to go about solving it...

Thanks a lot

Kushal
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by Arcane66 » Wed Oct 27, 2010 9:09 am
I love it when people post the wrong f**king equation and expect us to come up with the correct answer. Good work.
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by diebeatsthegmat » Mon Nov 01, 2010 9:53 am
alivapriyada wrote:
lokesh r wrote:
alivapriyada wrote:
diebeatsthegmat wrote:
alivapriyada wrote:The number of passengers on a certain bus at any given time is given by the equation P = -2(S - 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

A.9

B.6

C.4

D.2

E.1
to find the maximum one number ( P) you just need to minumun the other numbers (S)
P=-2(s-4)2+32=-4+16+32
thus skim the answer choices, only E is correct
OA is C not E
Are u sure the answer is C.

Because when s=4 , p =32
when s=1; p= -2(1-4)2+32= 12+32=44

I guess answer must be E.
yes m sure ,answer is C
this was the explanation provided in the MGMAT

The bus will carry its greatest passenger load when P is at its maximum value. If P = -2(S - 4)2 + 32, the maximum value of P is 32 because (S - 4)2 will never be negative, so the expression -2(S - 4)2 will never be positive. The maximum value for P will occur when -2(S - 4)2 = 0, i.e. when S = 4.

The correct answer is C.
so Aliva, is the quoation: p=-2(s-4)^2+32?
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by kushal.adhia » Mon Nov 01, 2010 10:40 am
@diebeatsthegmat

The correct statement, as u have mentioned, is p = -2(s-4)^2+32

I came across the same question when i took one of the tests...
Can u please explain how u came up with an answer for this question?

Thanks

Kushal
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