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OG11 #99- Red Herring?

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OG11 #99- Red Herring?

by VegasMBA » Tue Sep 02, 2008 7:10 pm
Hi Guys,

I tried to solve this problem and even after I read the explanation, I still could not figure out how to solve the question with the info given in the question. I understand the math in the explanation, in fact its quite simple.

How would you guys dice up this question? I feel like the n+1 info is a red herring...or am I completely missing the point?

On a scale that measures the intesity of a certain phenomenon, a reading of n+1 corresponds to an intensity that is 10 times the intensity corresponding to a reading of n. On that scale, the intensity corresponding to a reading of 8 is how many times as great as the intensity corresponding to a reading of 3?
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Problem Solving #99

by VegasMBA » Tue Sep 02, 2008 7:17 pm
Sorry for any confusion I may cause you. I thought I was already in the PS sub-forum.

The problem I am referring to is in the OG 11 #99 in problem solving
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Problem Solving #99

by VegasMBA » Tue Sep 02, 2008 7:18 pm
Sorry for any confusion I may cause you. I thought I was already in the PS sub-forum.

The problem I am referring to is in the OG 11 #99 in problem solving
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by bharathaitha » Thu Sep 04, 2008 6:41 am
reading at 8 is 10 times reading at 7. Reading at 7 is 10 times reading at 6 i.e. reading at 8 is 10^2 times reading at 6. Similarly if u solve further, u will figure out that reading at 8 is 10^5 times reading at 3.
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n+1

by VegasMBA » Thu Sep 04, 2008 9:27 am
So where does the "n+1" info come into play? That is what confused me when I read the question.
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by fatalmilk » Fri Sep 05, 2008 11:37 pm
The n+1 info is just to tell you that its the next corresponding reading on the scale. Without the n+1 info you wouldn't know what 10 times the intensity corresponds to and you would then have insufficient data to solve the problem.

Hope this makes sense to you now
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by just_do_it » Sat Sep 06, 2008 5:42 am
Assume the following,
intensity at reading n = x
therefore intensity at reading (n+1)=10x

n intensity
3 x
4 10x
5 100x, which is 10 times the intensity at n=4
6 1000x , which is 10 times the intensity at n=5
7 10000x , which is 10 times the intensity at n=6
8 100000x , which is 10 times the intensity at n=7

thus intensity at n=8 is 10^5 times the intensity at n=3.

Hope this helps.
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Junior | Next Rank: 30 Posts
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Thanks!

by VegasMBA » Sat Sep 06, 2008 9:17 am
Great, thanks so much guys!
That does make it clearer.
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