BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

GMAT Prep - Geometry Triangles

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pm
Location: INDIA
Thanked: 84 times
Followed by:3 members

by sudhir3127 » Mon Jul 14, 2008 10:53 pm
Is the OA E . sq root 3.?
Top
Senior | Next Rank: 100 Posts
Posts: 91
Joined: Sun Jul 13, 2008 10:36 pm
Thanked: 1 times
GMAT Score:770

by BlueRain » Mon Jul 14, 2008 10:55 pm
OA should be B.
Will explain if I were correct.
Top
Master | Next Rank: 500 Posts
Posts: 106
Joined: Sun Feb 17, 2008 10:09 pm
Thanked: 3 times

by ksh » Mon Jul 14, 2008 11:04 pm
when a triangle is inscribed in a cirle with diameter of the circle as one of the sides of the triangle, it will be a right angled triangle.


given that radius=1. so, diameter=2
one side=1

so by pythagorous, height of the triangle=sqrt3

and hence, area=sqrt3/2 which is B.
Top
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pm
Location: INDIA
Thanked: 84 times
Followed by:3 members

by sudhir3127 » Mon Jul 14, 2008 11:50 pm
if you use pythogorous theorem to find the hypoteneuse AB..

then my understanding is

AB^2 = BC^2 + AC^2
= 2^2+1^2= Sq root 5 and not not sq root 3.
Top
Senior | Next Rank: 100 Posts
Posts: 91
Joined: Sun Jul 13, 2008 10:36 pm
Thanked: 1 times
GMAT Score:770

by BlueRain » Mon Jul 14, 2008 11:54 pm
sudhir3127 wrote:if you use pythogorous theorem to find the hypoteneuse AB..

then my understanding is

AB^2 = BC^2 + AC^2
= 2^2+1^2= Sq root 5 and not not sq root 3.
The hypotenuse is AC, the right angle is at ABC, thus AC^2 = AB^2 + BC^2.
Top
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pm
Location: INDIA
Thanked: 84 times
Followed by:3 members

by sudhir3127 » Tue Jul 15, 2008 12:29 am
yeah .. got it .. thanks a lot...
Top
Legendary Member
Posts: 882
Joined: Fri Feb 20, 2009 2:57 pm
Thanked: 15 times
Followed by:1 members
GMAT Score:690

by crackgmat007 » Mon Jun 08, 2009 6:29 pm
Have a clarification - what are the angle measures of such triangle - is it 90:30:60?
Top
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

by tohellandback » Mon Jun 08, 2009 7:42 pm
Crackgmat,
you can't tell the angle measurements here.
it is a right triangle for sure but the other two angles can be anything.
Of course given some other conditions you might find the angles.

Thanks
The powers of two are bloody impolite!!
Top
Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Wed Nov 28, 2007 3:42 am
Location: Mumbai

by rajasiddarth » Mon Jun 08, 2009 10:57 pm
Hello tohellandback,

The angle formation is 30, 60 and 90.

If a right angled triangle has sides in the ratio of 1, sqrt3 and 2, we can say that the angles are of 30 60 and 90 respectively.

For 1, 1 and sqrt2 right angled traingles, angles formed are 45, 45 and 90
Top
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

by tohellandback » Mon Jun 08, 2009 11:05 pm
raja,
I think I mistook crackgmat's question. I thought he was asking about the triangle shown in the circle. You can't say what shape it can take unless you have Other information.

Thanks
The powers of two are bloody impolite!!
Top
Legendary Member
Posts: 882
Joined: Fri Feb 20, 2009 2:57 pm
Thanked: 15 times
Followed by:1 members
GMAT Score:690

by crackgmat007 » Tue Jun 09, 2009 9:43 pm
my question is more generic -- if one of the sides of a right triangle is the diameter, what are the angel measures? is it always 30 60 90? or varies?

(this question is not related to the problem in the topic)
Top
Legendary Member
Posts: 752
Joined: Sun May 17, 2009 11:04 pm
Location: Tokyo
Thanked: 81 times
GMAT Score:680

by tohellandback » Tue Jun 09, 2009 9:45 pm
yes crackgmat,
thats what I am saying.
You can't tell unless you have other conditions.

thanks
The powers of two are bloody impolite!!
Top
Post new topic Post Reply
• Page 1 of 1