Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

GMAT Prep - Geometry

Expert replies

by taketotask » Thu Aug 20, 2009 10:20 am
hey,

just looking at some of the explanations for this question. I believe PQO is a 45-45-90 triangle since PO and PQ are both radii of the circle then PO=PQ.

Knowing this, draw a line down from Q to the x-axis, let's call it point Z.

This forms another 45-45-90 triangle. Since QZ is 1, OZ must also be 1. Hence S = 1.

Hope this helps.
Join the discussion

Do we assume (0,0) for point O?

by ILAKSHMIR » Mon Aug 24, 2009 8:14 am
The solution for this problem holds only when we assume that O is the origin with co-ordinates (0,0). I am surprised that GMAT's q is not clearly worded. (Usually they are)

Do others share this view?
Join the discussion

by cat er ina » Sun Apr 25, 2010 6:51 am
kadishmj wrote:
akram wrote:
tutonaranjo wrote:No luck solving this. Please help.
Image
Options are:
a) 1/2
b) 1
c) sqrt 2
d) sqrt 3
e) sqrt 2 / 2
B is correct answer.

(s,t) will be (1, sqrt 3), radius is 2 .
Angle O is 60 degress on left and 30 degrees on right since sin 360=sqrt 3/2
B is correct, but akram's reasoning is not. I have no idea where he comes up with sin 360 = sqrt 3/2

It is a 30-60-90 triangle, and Angle O is 30 degrees on the left and 60 on the right (not what akram said). This may clear things up:

https://www.themathpage.com/aTrig/30-60-90-triangle.htm
THANKS FOR POSTING THIS LINK!!
Join the discussion

by r2kins » Sun Apr 25, 2010 7:25 am
lunarpower wrote:here's an awesome way to approach this.

see that 90 degree angle there? ok. that means that this question is really asking where the point (-rad3, 1) would go if the paper were rotated clockwise by 90 degrees.

so...

draw that point on your paper, and then physically rotate the paper by 90 degrees.

originally the x coordinate was -√3 (to the left). when you rotate the paper, this is now upward, so it's positive √3 in the y direction.
originally the y coordinate was positive 1 (upward). when you rotate the paper, this is now to the right, so it becomes positive 1 in the x direction.

ergo, new coordinates = (1, √3)

sweet
real sweet! jus a lil imagination and whoa...no calculation at all!
Join the discussion

by venmic » Thu Aug 26, 2010 3:30 pm
This is a mirror image problem
Step 1: Check the signs in the cooridnates
Step 2: Mirror the point (s,t) to (-^3,1)
tutonaranjo wrote:No luck solving this. Please help.
Image
Options are:
a) 1/2
b) 1
c) sqrt 2
d) sqrt 3
e) sqrt 2 / 2
Join the discussion

by skalevar » Mon Oct 18, 2010 5:32 pm
This might be a stupid question, but aren't diagrams in problem solving supposed to be accurate?

Upon initial inspection, it looks as if point S is the same height (1) and the same horizontal distance away from 0, just on the other side of the axis (sqrt 3).

I can see from the discussion that is incorrect, but can someone please explain why? I'd like to fully understand so I know when and when not to use the diagrams provided in PS.

Thanks!
Join the discussion

by Geva@EconomistGMAT » Tue Oct 19, 2010 12:49 am
skalevar wrote:This might be a stupid question, but aren't diagrams in problem solving supposed to be accurate?

Upon initial inspection, it looks as if point S is the same height (1) and the same horizontal distance away from 0, just on the other side of the axis (sqrt 3).

I can see from the discussion that is incorrect, but can someone please explain why? I'd like to fully understand so I know when and when not to use the diagrams provided in PS.

Thanks!
This question is the single exception to the "trust the diagram" rule that I recall ever seeing on any official materials - this diagram is supposed to be drawn to scale, but is clearly misleading.

By the GMAC's own instructions, GMAT diagrams are drawn to scale, so you can trust the figure, except for the following:
1) the figure explicitly states that the diagram is not drawn to scale (with the sentence: note: figure not drawn to scale)
2) In DS questions, the diagram conforms to the question stem, but not necessarily to the statements.

In simple words: trust the diagram in Problem solving questions (unless noted otherwise), but do not trust the diagram in DS questions - a DS diagram is probably there to make you think you know something that you don't really know until the statements tell you so. If a DS diagram presents a right triangle but doesn't explicitly label it as such, then the triangle can be drawn in a different way - until a statement later on will probably "lock" it as a right angle. Ignoring this property of DS diagrams is dangerous, as it affects you judgment of a sufficiency - you may think a statement is sufficient on its own, but that's because you assume the angle is a 90 degree just from the diagram, not from any information supplied by the question.
Geva
Senior Instructor
Master GMAT
1-888-780-GMAT
https://www.mastergmat.com
Join the discussion