BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

New DS

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 784
Joined: Sun Apr 03, 2011 3:51 amFollowed by: 12 members
Thanked: 114 times
by patanjali.purpose » Thu Sep 01, 2011 4:03 pm
If Z = |x+y|, is Z > 8

S1: x > 4
S2: |y| > 4

Pls suggest your innovative approach

OA E
Last edited by patanjali.purpose on Fri Sep 02, 2011 2:55 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Master | Next Rank: 500 Posts
Posts: 298
Joined: Tue Feb 16, 2010 1:09 amFollowed by: 1 member
Thanked: 2 times

by Deepthi Subbu » Thu Sep 01, 2011 7:16 pm
Is the OA E ?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 61
Joined: Tue Apr 13, 2010 3:29 am
Thanked: 8 times

by n@resh » Thu Sep 01, 2011 7:24 pm
patanjali.purpose wrote:If Z = |x+y|, is Z > 8

S1: x > 4
S2: |y| > 4

Pls suggest your innovative approach
Ans: E!

S1: X > 4 ...not sufficient as Value of Z depends on Y as well!
S2: |y| > 4... clearly not sufficient as Value of Z depends on Y too!

Combine both, yet we don't have clear values for x and y as it invloves Modulus sign.
Not sufficient.

Hence ans is E.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 608
Joined: Sun Jun 19, 2011 11:16 amFollowed by: 8 members
Thanked: 37 times

by saketk » Sat Sep 03, 2011 11:47 am
patanjali.purpose wrote:If Z = |x+y|, is Z > 8

S1: x > 4
S2: |y| > 4

Pls suggest your innovative approach

OA E
I hope you figured out that Statement 1 and statement 2 alone are not sufficient.

Let's combine them
the easy way is to plug numbers.

Let's take X=5

it is given that |y|>4 that means Y can be either positive or negative.

i.e. Either Y can be 5 or greater.. or -5 or lesser...

Clearly, even combining these two statement we will not get our answer.

Hence, E
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 398
Joined: Tue Jul 26, 2011 11:39 pmFollowed by: 6 members
Location: India
Thanked: 41 times

by prateek_guy2004 » Sat Sep 03, 2011 1:41 pm
At first glance i thought its C

If Z = |x+y|, is Z > 8

S1: x > 4

x is any no. greater than 4 not suff

S2: |y| > 4

y is any no. greater than 4 not suff

after combining both statement 2 has a modulus which can be +- inside..so not sufficient.

Hence E
Don't look for the incorrect things that you have done rather look for remedies....

https://www.beatthegmat.com/motivation-t90253.html
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1