The rate of a certain chemical reaction is directly proportional to the square of the concentration of chemical A present and inversely proportional to the concentration of B present. If the concentration of chemical B is increased by 100 percent, which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?
A) 100% decrease
B) 50% decrease
C) 40% decrease
D) 40% increase
E) 50% increase
OA - D
This question was already discussed, but I want to confirm if there is something wrong with my approach. Please let me know if I am missing something? This is how I solved.
Given,
The rate of a certain chemical reaction is directly proportional to the square of the concentration of chemical A present
R/A^2 = c
proportional to the concentration of B present.
R * B = C
If the concentration of chemical B is increased by 100 percent
2B --> to maintain the constant, we need to divide R by 2, hence
R/2 * 2B = C
which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?
(R/2)/A^2 must be equal to c. Can someone explain next steps? Tx much.
A) 100% decrease
B) 50% decrease
C) 40% decrease
D) 40% increase
E) 50% increase
OA - D
This question was already discussed, but I want to confirm if there is something wrong with my approach. Please let me know if I am missing something? This is how I solved.
Given,
The rate of a certain chemical reaction is directly proportional to the square of the concentration of chemical A present
R/A^2 = c
proportional to the concentration of B present.
R * B = C
If the concentration of chemical B is increased by 100 percent
2B --> to maintain the constant, we need to divide R by 2, hence
R/2 * 2B = C
which of the following is closest to the percent change in the concentration of chemical A required to keep the reaction rate unchanged?
(R/2)/A^2 must be equal to c. Can someone explain next steps? Tx much.
