BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

GMAT Prep #2 Quant help!

Share feedback about this free GMAT prep guide
Expert replies
by casalily » Fri Sep 28, 2012 8:45 am
So I did the GMAT Prep #2 yesterday and this question has been messing with my head every since. I'm not sure if I'm not seeing it right but I have no clue how they managed to get to the answer at all. I happen to be reviewing the questions before my exam (tomorrow) and I can't seem to solve this one.

So the question goes as follows:
When a certain tree was first planted, it was 4 ft tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
The correct answer is 2/3

My logic:
each year increase: x
If the plant was 4 ft the first year, then 6th year = 4 + 5x (as 2nd year - x, 3rd year - 2x, 4th year - 3x etc.) and 4th year = 4 + 3x
The different between both years = 1/5
So 6th - 4th = 2x
Therefore, 2x =1/5
and x = 1/10

I have been thinking and re-thinking but I have no clue how else to solve it. I'm clearly missing something obvious. Any ideas where I'm going wrong?
Join the discussion
Source: — The 60-Day GMAT Study Guide |

by Brent@GMATPrepNow » Fri Sep 28, 2012 9:11 am
casalily wrote: When a certain tree was first planted, it was 4 ft tall, and the height of the tree increased by a constant amount each year for the next 6 years. At the end of the 6th year, the tree was 1/5 taller than it was at the end of the 4th year. By how many feet did the height of the tree increase each year?
The correct answer is 2/3

My logic:
each year increase: x
If the plant was 4 ft the first year, then 6th year = 4 + 5x (as 2nd year - x, 3rd year - 2x, 4th year - 3x etc.) and 4th year = 4 + 3x
The different between both years = 1/5
So 6th - 4th = 2x
Therefore, 2x =1/5
and x = 1/10

I have been thinking and re-thinking but I have no clue how else to solve it. I'm clearly missing something obvious. Any ideas where I'm going wrong?
You were on the right track. Just one small problem, which I highlighted above in blue.

Height of tree day 0 = 4
Let d be the increased height each year
Height of tree at the end of the 1st year = 4+d
Height of tree at the end of the 2nd year = 4+d+d = 4+2d
Height of tree at the end of the 3rd year = 4+d+d+d = 4+3d
Height of tree at the end of the 4th year = 4+d+d+d+d = 4+4d
Height of tree at the end of the 5th year = 4+d+d+d+d+d = 4+5d
Height of tree at the end of the 6th year = 4+d+d+d+d+d+d = 4+6d

We are told that 4+6d is 1/5 greater than 4+4d
In other words 4+6d = (4+4d) + 1/5(4+4d)
or 4+6d = 6/5(4+4d)
Multiply both sides by 5 and (to eliminate fractions) and solve for d to get d=2/3

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by casalily » Fri Sep 28, 2012 11:16 am
I can see where I went wrong - I think I was looking at the question as the difference between 6th and 4th year was equal to 1/5.
The wording of the question is throwing me off still because it says the 6th year is 1/5 greater than the 4th year and have expressed that as 6th year = (4+4d) +1/5(4+4d) so it wouldn't be right to say 6th year = (4+4d) = (1/5), yes?
So the logic behind it is that you know it's 1/5 greater but since you don't know the value of the 4th itself (namely, a number), you need to add 4th year + 1/5(4th year) - am I following it correctly?

Thanks a lot for the prompt response!
Join the discussion