attached
first 1 OA A
second 1 OA C
specifically can you tell me what the quickest way is to sovle each.
i find myself pondering a lot on geom qs
thanks[/img]
5-Day Free Trial
5-day free, full-access trial TTP
Available with Beat the GMAT members only code
MORE DETAILS
2 tough gmat prep geom qs
This topic has expert replies
-
gauravgundal
- Master | Next Rank: 500 Posts
- Posts: 199
- Joined: Mon Apr 06, 2009 4:15 am
- Location: India
- Thanked: 13 times
OK.
Answer to First Question
tri BDC - iso triangle therefore bd=bc
now angle adb=180-2x
thus angle abd=x
thus triadb - iso triangle therefore da=db=bc
thus answer is A
while Stmt 2 is insuff
Answer to First Question
tri BDC - iso triangle therefore bd=bc
now angle adb=180-2x
thus angle abd=x
thus triadb - iso triangle therefore da=db=bc
thus answer is A
while Stmt 2 is insuff
2nd Question
Lets assume O is the centre of the circle
angle ABC = 60
therefore angle AOC = 120
Degree measure of arc ABC = 360-120 - 240
length of arc ABC = 2*pi*r * (degree measure of the arc ABC/360)
24 = 2*pi*r * (240/360)
2*r = 36/3.14
2*r < 12 but > 9
Choose C
Lets assume O is the centre of the circle
angle ABC = 60
therefore angle AOC = 120
Degree measure of arc ABC = 360-120 - 240
length of arc ABC = 2*pi*r * (degree measure of the arc ABC/360)
24 = 2*pi*r * (240/360)
2*r = 36/3.14
2*r < 12 but > 9
Choose C
SACX
