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2 tough gmat prep geom qs

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by gauravgundal » Mon Jun 01, 2009 10:32 pm
OK.

Answer to First Question

tri BDC - iso triangle therefore bd=bc
now angle adb=180-2x
thus angle abd=x
thus triadb - iso triangle therefore da=db=bc

thus answer is A

while Stmt 2 is insuff
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by sacx » Tue Jun 02, 2009 4:10 am
2nd Question

Lets assume O is the centre of the circle

angle ABC = 60
therefore angle AOC = 120
Degree measure of arc ABC = 360-120 - 240

length of arc ABC = 2*pi*r * (degree measure of the arc ABC/360)
24 = 2*pi*r * (240/360)

2*r = 36/3.14
2*r < 12 but > 9

Choose C
SACX
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