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DS- x>3

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Source: — Data Sufficiency |

by liferocks » Wed May 19, 2010 8:48 pm
From 1

(x-1)>2 or (x-1)<-2
or x>3 or x<-1...not sufficient

From 2
(x-2)>3 or (x-2)<-3

or x>5 or x<-1..not sufficient

combining
x<-1.or x>5..not sufficient

Ans option E
Last edited by liferocks on Wed May 19, 2010 9:50 pm, edited 1 time in total.
"If you don't know where you are going, any road will get you there."
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by krazy800 » Wed May 19, 2010 8:54 pm
liferocks wrote:From 1

(x-1)>2 or (x-1)<-2
or x>3 or x<-1...not sufficient

From 2
(x-2)>3 or (x-2)<-3

or x>5 or x<-1..not sufficient

combining
x<-1...sufficient

Ans option C
IMO E

combining statements I and II

x<-1 or x>5

so E

plz correct me if am wrong
Aiming High
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by liferocks » Wed May 19, 2010 9:50 pm
krazy800 wrote:
liferocks wrote:From 1

(x-1)>2 or (x-1)<-2
or x>3 or x<-1...not sufficient

From 2
(x-2)>3 or (x-2)<-3

or x>5 or x<-1..not sufficient

combining
x<-1...sufficient

Ans option C
IMO E

combining statements I and II

x<-1 or x>5

so E

plz correct me if am wrong
hmm..agree with E.I have edited the post.Thanks for pointing out.
"If you don't know where you are going, any road will get you there."
Lewis Carroll
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by Rafter » Thu May 20, 2010 1:20 pm
It should be D . OA please.
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by Patrick_GMATFix » Fri May 21, 2010 10:26 am
Statement (1): (x-1)^2 > 4.
for the square of the left side to be more than 4, what's inside the parentheses must be greater than 2 (meaning x must be greater than 3) or what's inside the parentheses must be less than -2 (meaning x is smaller than -1). Because x is positive, the 2nd possibility is invalid and x must be greater than 3. (1) is sufficient.

Statement (2) can be solved in a very similar way and also found sufficient.

Answer is D. This is QID 1475

-Patrick
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by kel2010 » Fri May 21, 2010 1:52 pm
ans should be D.

for statement I all values above 3 give desired result
for statement II all vales above 5 give desired result.
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by nicajvch » Tue May 25, 2010 11:26 am
Why wouldnt it be the same for number less than -3?
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by T11 » Wed May 26, 2010 9:02 am
The Q says x is positive.

So, (x-1) cannot <= -2
ans similarly (x-2) cannot <= -3

Hence Both I & II are sufficient.
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by sumanr84 » Wed May 26, 2010 10:40 am
tricky !!

People always miss small details like this one " x>0 " ( I too missed :()
I am on a break !!
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