From 1

(x-1)>2 or (x-1)<-2
or x>3 or x<-1...not sufficient

From 2
(x-2)>3 or (x-2)<-3

or x>5 or x<-1..not sufficient

combining
x<-1.or x>5..not sufficient

Ans option E

liferocks wrote:From 1

(x-1)>2 or (x-1)<-2
or x>3 or x<-1...not sufficient

From 2
(x-2)>3 or (x-2)<-3

or x>5 or x<-1..not sufficient

combining
x<-1...sufficient

Ans option C

IMO E

combining statements I and II

x<-1 or x>5

so E

plz correct me if am wrong

krazy800 wrote:

liferocks wrote:From 1

(x-1)>2 or (x-1)<-2
or x>3 or x<-1...not sufficient

From 2
(x-2)>3 or (x-2)<-3

or x>5 or x<-1..not sufficient

combining
x<-1...sufficient

Ans option C

IMO E

combining statements I and II

x<-1 or x>5

so E

plz correct me if am wrong

hmm..agree with E.I have edited the post.Thanks for pointing out.

It should be D . OA please.

Statement (1): (x-1)^2 > 4.
for the square of the left side to be more than 4, what's inside the parentheses must be greater than 2 (meaning x must be greater than 3) or what's inside the parentheses must be less than -2 (meaning x is smaller than -1). Because x is positive, the 2nd possibility is invalid and x must be greater than 3. (1) is sufficient.

Statement (2) can be solved in a very similar way and also found sufficient.

Answer is D. This is QID 1475

-Patrick

ans should be D.

for statement I all values above 3 give desired result
for statement II all vales above 5 give desired result.

Why wouldnt it be the same for number less than -3?

The Q says x is positive.

So, (x-1) cannot <= -2
ans similarly (x-2) cannot <= -3

Hence Both I & II are sufficient.

tricky !!

People always miss small details like this one " x>0 " ( I too missed )