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GMAT Practice exam 2 - Rations

This topic has 5 expert replies and 3 member replies
lucas211 Senior | Next Rank: 100 Posts Default Avatar
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GMAT Practice exam 2 - Rations

Post Sat Jun 04, 2016 1:50 am
Hello BTG

Would appreciate a little help to the fastest approach to this ratio-question:



Thanks in advance

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GMAT/MBA Expert

Post Thu Sep 21, 2017 7:37 pm
Hi rsarashi,

Although you did not show your work, I assume that you calculated the K = 150 and A = 90. While you are correct that the difference in those two numbers is 60, the question asks for the difference AFTER Kaye has given Alberto 10 stamps. After the gift, Kaye would have 140 stamps and Alberto would have 100 stamps.

Final Answer: 40; C

GMAT assassins aren't born, they're made,
Rich

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pannalal Junior | Next Rank: 30 Posts Default Avatar
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Post Thu Sep 21, 2017 9:06 pm
Given that the ratio of stamps between Kaye and Alberto is 5:3.
Assuming Kaye has 5x and Alberto has 3x stamps. When Kaye gives 10 of her stamps to Alberto, the ratio becomes 7:5.

Thus, (5x-10)/(3x+10) = 7/5
or 25x - 50 = 21x + 70
or 4x = 120
or x = 30.

Kaye has stamps = 5x - 10 = 140
Alberto has stamps = 3x + 10 = 100

Kaye has more stamps than Alberto = 140-100 = 40 stamps.

Answer: C

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Post Sat Jun 04, 2016 2:24 am
Quote:
The number of stamps that Kaye and Alberto had were in the ratio 5:3 respectively. After Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?

20
30
40
60
900
The answer choices imply that the values in the problem are all MULTIPLES OF 10.

Since K:A = 5:3, the following options are implied:
K=50, A=30
K=100, A=60
K=150, A=90
K=200, A=120.

After K gives away 10 stamps and A receives 10 stamps, the resulting values for K and A must be in a ratio of 7 to 5:
K=40, A=40
K=90, A=70
K=140, A=100.
We can stop here, since 140:100 = 14:10 = 7:5.

Thus, after the exchange, K-A = 140-100 = 40.

The correct answer is C.

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lucas211 Senior | Next Rank: 100 Posts Default Avatar
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Post Sat Jun 04, 2016 2:49 am
GMATGuruNY wrote:
Quote:
The number of stamps that Kaye and Alberto had were in the ratio 5:3 respectively. After Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?

20
30
40
60
900
The answer choices imply that the values in the problem are all MULTIPLES OF 10.

Since K:A = 5:3, the following options are implied:
K=50, A=30
K=100, A=60
K=150, A=90
K=200, A=120.

After K gives away 10 stamps and A receives 10 stamps, the resulting values for K and A must be in a ratio of 7 to 5:
K=40, A=40
K=90, A=70
K=140, A=100.
We can stop here, since 140:100 = 14:10 = 7:5.

Thus, after the exchange, K-A = 140-100 = 40.

The correct answer is C.
Hi GMATGuru

Thanks for you reply.
I think I am missing the point; how do the answer choices imply that the values in the problem are all multiples of 10?

Thanks again

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Post Sat Jun 04, 2016 3:00 am
lucas211 wrote:
Hi GMATGuru

Thanks for you reply.
I think I am missing the point; how do the answer choices imply that the values in the problem are all multiples of 10?

Thanks again
Since all of the answer choices are multiples of 10, the values in the problem are also probably multiples of 10.

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GMAT/MBA Expert

Post Sat Jun 04, 2016 8:50 am
Quote:
The number of stamps that Kaye and Alberto had were in the ratio 5 : 3, respectively. After Kaye gave Alberto 10 of her stamps,the ratio of the number Kaye had to the number Alberto had was 7 : 5. As a result of this gift, Kaye had how many more stamps than Alberto?
A. 20
B. 30
C. 40
D. 6O
E. 9O
Another option is to solve the question using TWO VARIABLES.
Let K = # of stamps K had after the exchange
Let A = # of stamps A had after the exchange
This means that K+10 = # of stamps K had before the exchange
This means that A-10 = # of stamps A had before the exchange

Note: Our goal is to find the value of K-A

The number of stamps that K and A (originally) had were in the ratio 5:3
So, (K+10)/(A-10) = 5/3
We want a prettier equation, so let's cross multiply to get 3(K+10) = 5(A-10)
Expand: 3K + 30 = 5A - 50
Rearrange: 3K - 5A = -80

After K gave A 10 of her stamps, the ratio of the number K had to the number A had was 7:5
So, K/A = 7/5
We want a prettier equation, so let's cross multiply to get 5K = 7A
Rearrange to get: 5K - 7A = 0

At this point we have two equations:
5K - 7A = 0
3K - 5A = -80

Our goal is to find the value of K - A.
IMPORTANT: We need not solve for the individual values of K and A. This is great, because something nice happens when we subtract the blue equation from the red equation.
We get: 2K - 2A = 80
Now divide both sides by 2 to get: K - A = 40

Answer: C

Cheers,
Brent

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rsarashi Master | Next Rank: 500 Posts Default Avatar
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Post Thu Sep 21, 2017 9:26 am
Hello Experts ,

I got my two equations like below.

K/A = 5/3
&
K-10/A+10 = 7/5

If i solve this i get the difference of 60

Please let me know where i am getting wrong.

Thanks.

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Post Mon Sep 25, 2017 3:30 pm
Quote:
The number of stamps that Kaye and Alberto had were in the ratio 5:3 respectively. After Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7:5. As a result of this gift, Kaye had how many more stamps than Alberto?

20
30
40
60
900
We are given that the number of stamps that Kaye and Alberto had was in the ratio 5 : 3. We can represent this as:

K : A = 5x : 3x

We are next given that after Kaye gave Alberto 10 of her stamps, the ratio of the number Kaye had to the number Alberto had was 7 : 5. Using this information, we can create the following equation:

(5x - 10)/(3x + 10) = 7/5

5(5x - 10) = 7(3x + 10)

25x - 50 = 21x + 70

4x = 120

x = 30

Kaye now has 5(30) - 10 = 140 stamps and Alberto has 3(30) + 10 = 100 stamps. So Kaye has 140 - 100 = 40 more stamps than Alberto has.

Answer: C

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