Frieda walks 6 feet per second, a pace which is 1/3 as fast as Evita's pace. If Evita's pace is twice as fast as Pablo's then how many feet does Pablo walk in an hour?
A. 129,600
B. 64,800
C. 32,400
D. 3,600
E. 540
The OA is C.
I got confused with the equations. Can anyone help me? Please. I'd be thankful.
Frieda walks 6 feet per second, a pace which is 1/3 as
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Since Frieda's rate is 1/3 Evita's rate, Evita's rate is 3 times Frieda's rate:M7MBA wrote:Frieda walks 6 feet per second, a pace which is 1/3 as fast as Evita's pace. If Evita's pace is twice as fast as Pablo's then how many feet does Pablo walk in an hour?
A. 129,600
B. 64,800
C. 32,400
D. 3,600
E. 540
3*6 = 18 feet per second.
Since Evita's rate is twice Pablo's rate, Pablo's rate is 1/2 Evita's rate:
(1/2)(18) = 9 feet per second.
How many feet does Pablo walk in an hour?
Since Pablo's rate is 9 feet per second, and 1 hour is the equivalent of 3600 seconds, we get:
Pablo's distance = rt = (9 feet per second)(3600 seconds) = 32,400 feet.
The correct answer is C.
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The rate of Frieda is 6 feet per second, and that rate is 1/3 as fast as Evita's rate. Thus,M7MBA wrote:Frieda walks 6 feet per second, a pace which is 1/3 as fast as Evita's pace. If Evita's pace is twice as fast as Pablo's then how many feet does Pablo walk in an hour?
A. 129,600
B. 64,800
C. 32,400
D. 3,600
E. 540
1/3(Evita's rate) = 6
Evita's rate = 18 feet per second
Since Evita's rate is twice as fast as Pablo's rate, Pablo's rate is 18/2 = 9 feet per second.
Thus, Pablo can walk 9 x 3,600 = 32,400 feet in an hour.
(Note: 1 hour = 3,600 seconds)
Answer: C
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