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50 children attended a carnival where cotton candy

Expert replies
by AAPL » Fri Jun 29, 2018 6:36 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

50 children attended a carnival where cotton candy and ice cream were sold. If 14 children ate only cotton candy, 18 children ate only ice cream, and 8 children had neither cotton candy nor ice cream, how many children ate ice cream?

A. 18
B. 20
C. 24
D. 28
E. 32

The OA is D.

This is an approach to solving this question (Double Matrix Method),

1. 14 children only cotton candy, 18 only ice cream, and 8 children no cotton candy and ice cream.
2. Only one left category: both ate cotton candy and ice cream, which is 50 - 14 - 18 - 8 = 10.
3. Thus, children who ate ice cream = children ONLY ate ice cream + BOTH = 18 + 10 = 28.

Has anyone another strategic approach to solve this PS question? Regards!
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Source: — Problem Solving |

by Jay@ManhattanReview » Sun Jul 01, 2018 10:41 pm
AAPL wrote:50 children attended a carnival where cotton candy and ice cream were sold. If 14 children ate only cotton candy, 18 children ate only ice cream, and 8 children had neither cotton candy nor ice cream, how many children ate ice cream?

A. 18
B. 20
C. 24
D. 28
E. 32

The OA is D.

This is an approach to solving this question (Double Matrix Method),

1. 14 children only cotton candy, 18 only ice cream, and 8 children no cotton candy and ice cream.
2. Only one left category: both ate cotton candy and ice cream, which is 50 - 14 - 18 - 8 = 10.
3. Thus, children who ate ice cream = children ONLY ate ice cream + BOTH = 18 + 10 = 28.

Has anyone another strategic approach to solve this PS question? Regards!
This is perfect.

-Jay
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by Shahrukh_mbabreakspace » Mon Jul 02, 2018 5:12 am
Let A be children eating Candy and B be children eating Ice cream

Then A union B is children eating atleast one thing
We know,
AUB= A+B-(A intersection B)= Only A+ Only B +(A intersection B)

Now, A union B= 50- 8= 42
42= 14 + 18 + x
x=10

So, total people who eat ice cream= 18+10= 28
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by Scott@TargetTestPrep » Wed Jul 04, 2018 6:13 pm
AAPL wrote:50 children attended a carnival where cotton candy and ice cream were sold. If 14 children ate only cotton candy, 18 children ate only ice cream, and 8 children had neither cotton candy nor ice cream, how many children ate ice cream?

A. 18
B. 20
C. 24
D. 28
E. 32
We can create the following equation:

total children = # ate ice cream only + # ate cotton candy only + # ate both + # ate neither

50 = 18 + 14 + b + 8

50 = b + 40

10 = b

Since 10 children ate both ice cream and cotton candy, we add these 10 to the 18 children who ate only ice cream to get 10 + 18 = 28 children who ate ice cream.

Answer: D

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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