In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?
A. 2
B. 1
C. 0
D. -1
E. -2
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GMAT Official Guide 2019 In the xy-coordinate plane
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BTGmoderatorDC
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KEY CONCEPT: In order for a point to be ON a line, the x- and y-coordinates of the point must satisfy the equation of that lineBTGmoderatorDC wrote:In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?
A. 2
B. 1
C. 0
D. -1
E. -2
So, for example, the point (3,7) lies ON the line defined by the equation y = 2x + 1, because x = 3 and y = 7 satisfy the equation y = 2x + 1
That is, 7 = 2(3) + 1
So, if the point (0,2) lies on the graph of the line 2x + ky = 4, then x = 0 and y = 2 must satisfy the equation 2x + ky = 4
Replace x and y with 0 and 2 to get: 2(0) + (k)(2) = 4
Simplify: 0 + 2k = 4
Solve: k = 2
Answer: A
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Scott@TargetTestPrep
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We can substitute 0 for x and 2 for y and solve for k:BTGmoderatorDC wrote:In the xy-coordinate plane, if the point (0,2) lies on the graph of the line 2x + ky = 4, what is the value of the constant k ?
A. 2
B. 1
C. 0
D. -1
E. -2
2(0) + k(2) = 4
2k = 4
k = 2
Answer: A
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[1] Translate Coordinates to X and Y
A point on a Cartesian plane always follows the (x, y) format.
For this problem, (0, 2) corresponds to an x value of 0 and a y value of 2.
[2] Plug X and Y Into Line Formula
2x + ky = 4
2(0) + k(2) = 4
0 + 2k = 4
k = 2
A point on a Cartesian plane always follows the (x, y) format.
For this problem, (0, 2) corresponds to an x value of 0 and a y value of 2.
[2] Plug X and Y Into Line Formula
2x + ky = 4
2(0) + k(2) = 4
0 + 2k = 4
k = 2
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Bijaya Krushna Mohapatra
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the Point is (0,2)
So 2x +Ky =4
putting the value of x and y we will get
k.2= 4
K=2
So ans . (A)
So 2x +Ky =4
putting the value of x and y we will get
k.2= 4
K=2
So ans . (A)
