Question 1 (in future, please only post 1 question per thread, makes it easier for everyone to follow along):
First, we need to understand the sequence.
Basically, odd numbered terms equal the number of the term. So, the 1st term =1, the 3rd term =3, the 5th term =5 and so on.
Even numbered terms equal negative the previous term. So, the 2nd term = -1, the 4th term = -3, the 6th term = -5 and so on.
So, the sequence is:
{1, -1, 3, -3, 5, -5, 7, -7, ...}
The question is:
Is the sum of the terms positive?
Looking at our sequence, we can see that each pair of terms sums to 0. So, if we have an odd number of terms, the sum will be positive; if we have an even number of terms, the sum will be 0.
Let's look at the statements:
(1) n is odd.
Odd number of terms, therefore YES, the sum will be positive: sufficient.
(2) a(n) is positive.
If the nth term is positive, then n must be an odd number (since all the even numbered terms are negative). Therefore we have an odd number of terms and YES, the sum will be positive: sufficient.
Each of 1 and 2 is sufficient alone: choose (d).