Given xy=1 What is the value of 2(x+y)^2/ 2(x-y)^2=?
The answer 16..
My answer is :
=2( x^2 + 2xy + y^2 ) / 2( x^2 - 2xy + y^2 )
= x^2 + 2(1) + y^2 / x^2 - 2(1) + y^2
I stopped here.. can someone continue please ?
Given xy=1 What is the value of ?
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- logitech
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Hint X=1/YAbdulla wrote:Given xy=1 What is the value of 2(x+y)^2/ 2(x-y)^2=?
The answer 16..
My answer is :
=2( x^2 + 2xy + y^2 ) / 2( x^2 - 2xy + y^2 )
= x^2 + 2(1) + y^2 / x^2 - 2(1) + y^2
I stopped here.. can someone continue please ?
LGTCH
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Given xy=1 What is the value of 2(x+y)^2/ 2(x-y)^2=?
The answer 16..
There is a typo in this problem. If I am not mistaken it should read
2 ^ (x+y) ^ 2 / 2 ^(x-y)^2
= 2 ^ (x^2+y^2+2xy) / 2 ( x^2+y^2-2xy)
(a^m / a ^n = a^ (m-n) where a =2 m = x^2+y^2+2xy n = x^2+y^2-2xy)
= 2 ^ (x^2+y^2+2xy-x^2-y^2+2xy)
= 2 ^ 4xy
= 2 ^ 4(1)
=16
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I'm idiot ... Thats why the x & y letters were very small on the screen .. I was asking myself why its too small, but never think its exponents... FUNNY
Thank you Cramya
Thank you Cramya
Abdulla
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- harshavardhanc
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as the question doesn't have other conditions except XY=1,
take x=y=1, substitute and be happy!
take x=y=1, substitute and be happy!
Regards,
Harsha
Harsha