Anurag,
Can this be taken as like this also?
n = a^x * b^y implies number of divisors of n = (x + 1)(y + 1)
Is it, n = a^x implies number of divisors of n = (x + 1)
How does it work for a number 36?
36 = 2^2 * 3^2
Which implies there should be (2+1) (2+1)
ie. 9 divisors
Divisors of 36 - 2,3,4,6,9,12,18,36 (we have only 8, is "1" also to be done included in each instances.?????
Anurag@Gurome wrote:karthikpandian19 wrote:If pand q are prime numbers, how many divisors does the product p^3q^6 have?
(A) 9 (B) 12(C) 18(D) 28(E) 36[/list]
When we have to find the number of divisors of a number, then factorize the number into its prime factors, like, n = a^x * b^y, where a, b are distinct prime factors of n, and x, y are powers of prime factors a and b respectively.
Then number of divisors of n = (x + 1)(y + 1)
Here number of divisors of p^3 * q^6 = (3 + 1)(6 + 1) = 4 * 7 =
28
The correct answer is
D.
