There are two concentric circles such that the area of the outer circle is four times the area of the inner circle. Let A, B, and C be three distinct points on the perimeter of the outer circle such that AB and AC are tangents to the inner circle. If the area of the triangle ABC is 9Root3/PI square centimeters, then the area of the outer circle is:
A) 9/4
B) 9/PI
C) 12
D) 12 pi
E) 12Root3
When i assume given triangle to be an equilateral then i can solve it.
A) 9/4
B) 9/PI
C) 12
D) 12 pi
E) 12Root3
When i assume given triangle to be an equilateral then i can solve it.
