Sure.
We know that all the triangles are equilateral and that the sides of the larger triangle are 2 times bigger. I basically plugged in numbers to figure out the area.
So, for the large triangle, lets make the side length=4. To find the area, we apply the (bh)/2 formula. B/c its equilateral, we know that the height will break about the equilateral into two identical 30-60-90 right triangles. So, the side=4 is our hypotenuse, and the height will be 4/2 (sqrt 3) or 2 (sqrt 3). Thus, the area of the large triangle is [4* 2(sqrt 3)]/2 = 4(sqrt 3).
Lets now look at the smaller triangles. We know that the length of the smaller equilateral is half of that of the larger. So, given that I used 4 for the larger side, here we'll use half of that which is 2. Again, same concept applies, we come up with two identical 30-60-90 right triangles and our height will be (sqrt 3). The area then of one small equilateral is [2*(sqrt 3)]/2 = (sqrt 3).
Compare the area of the larger to that of the smaller. Smaller triangle area is 1/4 that of the larger triangle. So if we take out that one small unshaded triangle, we are left with 3(sqrt 3) which is 3/4K where K=area of the large triangle.
Hope that helps.