Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Geometry Question

Expert replies
by RBF3 » Sun Jul 17, 2011 2:59 pm
I took an educated guess on this question but I was wondering why C was the answer?


Image

Thanks for any help
Join the discussion
Source: — Problem Solving |

by RBF3 » Sun Jul 17, 2011 3:16 pm
Meant to post this in data sufficiency, sorry.
Join the discussion

by knight247 » Mon Jul 18, 2011 12:15 am
Does look a little complicated but a fairly simple one. Explanation as follows.

(1)in triangle RSQ
qr=rs
So it follows that
angle rqs= angle rsq = y degrees (in a triangle, sides opposite congruent angles are equal)

Now, measure of angles qrs+rqs+rsq=180 (property of triangles)
qrs+y+y=180
qrs=180-2y.......(a)

Insufficient.

(2)in triangle STU
ST=TU
angle sut = angle tsu = z degrees (in a triangle, sides opposite congruent angles are equal)

similarly
measure of angles tsu+sut+stu=180 (property of triangles)
z+z+stu=180
stu=180-2z......(b)

Insufficient

Combining (1) and (2)

In triangle RPT

angle prt + angle rtp + angle rpt =180

180-2y+180-2z+90=180 (since angle qrs=angle prt, angle stu=angle rtp and from 1 and 2)
solving we get
y+z=135.....(c)

now,
angle rsq+angle qsu+angle tsu=180
y+x+z=180

x=180-(y+z)
x=180-135=45

Hence C. Hope this explanation helps.

Have added an image to clarify
You do not have the required permissions to view the files attached to this post.
Join the discussion

by Anurag@Gurome » Mon Jul 18, 2011 3:45 am
RBF3 wrote:I took an educated guess on this question but I was wondering why C was the answer?


Image

Thanks for any help
Note that the measure of angle x depends upon the position of points Q, S and U only. Unless we don't know the fixed positions of these three points, we cannot uniquely determine the measure of angle x.

Statement 1: QR = RS
Thus position of Q and S is fixed. But U can be any point on PT and accordingly value of x will be different.

Not sufficient

Statement 2: ST = TU
Thus position of S and U is fixed. But Q can be any point on PR and accordingly value of x will be different.

Not sufficient

1 & 2 Together: Now the three points are fixed. Let's see whether we can find x. Refer to the image below.
Image

On point S, the sum of the three angles must be equal to 180°.
Thus, (x + y + z) = 180° ..................................... (i)

angle PQS = (180° - angle RQS) = (180° - z)
angle PUS = (180° - angle TUS) = (180° - y)

Now in quadrilateral PQSU,
  • Sum of all the internal angles = 360°
    => [x + 90° + (180° - y) + (180° - z)] = 360°
    => (x - y - z + 90°) = 0 .................................. (ii)
Now add (i) and (ii) => (2x + 90°) = 180° => x = 45°

Sufficient

The correct answer is C.
Anurag Mairal, Ph.D., MBA
GMAT Expert, Admissions and Career Guidance
Gurome, Inc.
1-800-566-4043 (USA)

Join Our Facebook Groups
GMAT with Gurome
https://www.facebook.com/groups/272466352793633/
Admissions with Gurome
https://www.facebook.com/groups/461459690536574/
Career Advising with Gurome
https://www.facebook.com/groups/360435787349781/
Join the discussion