sanchu wrote:13th Edition Question Number 92.
A ladder of a fire truck is elevated to an angle of 60 degrees and extended to a length of 70 feet. If the base of the ladder is 7 feet above ground, how many feet above the ground does the ladder reach?
The answer set mentions that this is a 30-60-90 triangle. How would I have deduced this part? I visualized correctly, but I didn't know how to solve.
When ladder BC is elevated to an angle of 60 degrees, the result is ∆ABC.
Since AB is perpendicular to the ground, ∠BAC is a right angle.
Thus, ∆ABC is a 30-60-90 triangle.
In a 30-60-90 triangle, the sides are in the following ratio:
s : s√3 : 2s.
In ∆ABC, 2s = 70, implying that s=35.
Thus, the length of AB -- the middle side -- is 35√3.
Since the base of the ladder -- point C -- is 7 feet off the ground, the total distance between point B and the ground = [spoiler]35√3 + 7[/spoiler].
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