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Start the plan$$\frac{\left(3^{-1}+4^{-1}\right)^{-2}}{\frac{4^2}{7^2}}=$$ A. \(\frac{12}{9}\)
B. \(\frac{49}{144}\)
C. \(\frac{12}{7}\)
D. \(7\)
E. \(9\)
[spoiler]OA=E[/spoiler]
Source: Veritas Prep
B. \(\frac{49}{144}\)
C. \(\frac{12}{7}\)
D. \(7\)
E. \(9\)
[spoiler]OA=E[/spoiler]
Source: Veritas Prep
