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For the students in a Physical Fitness Class Section #1, the

Expert replies
by subh2273 » Sun Oct 07, 2018 10:57 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ?

(1) R < S

(2) X > Y
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Source: — Data Sufficiency |

subh2273 wrote:For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ?

(1) R < S

(2) X > Y
\[{\text{range}} = {V_{\max }} - {V_{\min }}\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{V_{\min }} = {V_{\max }} - {\text{range}}\]
Section 1: weights have minimum value (X-R) kg and maximum value X kg.
Section 2: weights have minimum value (Y-S) kg and maximum Y kg.
\[X - R\,\,\,\mathop > \limits^? \,\,Y - S\]
\[\left( 1 \right)\,\,R < S\,\,\,\,\,\,\left\{ \begin{gathered}
\,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {90,10,90,20} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{YES}}} \right\rangle \,\,\,\,\,\,\left( {80\,\,\mathop > \limits^? \,70} \right) \hfill \\
\,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {80,10,90,20} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{NO}}} \right\rangle \,\,\,\,\,\,\,\,\left( {70\,\,\mathop > \limits^? \,70} \right) \hfill \\
\end{gathered} \right.\]
\[\left( 2 \right)\,\,X > Y\,\,\,\,\,\left\{ \begin{gathered}
\,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {90,10,80,10} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{YES}}} \right\rangle \,\,\,\,\,\,\left( {80\,\,\mathop > \limits^? \,70} \right) \hfill \\
\,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {90,20,80,10} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{NO}}} \right\rangle \,\,\,\,\,\,\,\,\left( {70\,\,\mathop > \limits^? \,70} \right) \hfill \\
\end{gathered} \right.\]
\[\left( {1 + 2} \right)\,\,\,\,\left\{ \begin{gathered}
\,\,R < S\,\,\, \Rightarrow \,\,\,\, - R > - S \hfill \\
\,\,X > Y \hfill \\
\end{gathered} \right.\,\,\,\,\,\,\,\,\mathop \Rightarrow \limits^{\left( + \right)} \,\,\,\,\,\,\,X + \left( { - R} \right)\,\, > \,\,Y + \left( { - S} \right)\,\,\,\,\, \Rightarrow \,\,\,\left\langle {{\text{YES}}} \right\rangle \,\]

The correct answer is therefore (C).

This solution follows the notations and rationale taught in the GMATH method.

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Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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by Jay@ManhattanReview » Wed Oct 10, 2018 9:33 pm
subh2273 wrote:For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ?

(1) R < S

(2) X > Y
Given:

"¢ Section 1: Range = R; Highest weight = X, thus, Lowest weight = X - R
"¢ Section 2: Range = S; Highest weight = Y, thus, Lowest weight = Y - S

Question: Is X - R > Y - S?

Let's take each statement one by one.

(1) R < S

Case 1: If X > Y, then X - R > Y - S => X - Y > R - S => |X - Y| > -|R - S|, which is ALWAYS correct, irespective of values of X, Y, R, and S.
Case 2: If X < Y, then X - R > Y - S => X - Y > R - S => -|X - Y| > -|R - S|, which is NOT necessarily correct since both |X - Y| and |R - S| are negative numbers, they cannot be compared untill we have their unique values.

Insufficient.

(2) X > Y

As with Statement 1, same with Statement 2. Insufficient.

(1) and (2) together

Case 1 discussed in Statement 1 is applicable, thus, X - R > Y - S. The answer is Yes. Sufficient.

The correct answer: C

Hope this helps!

-Jay
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by GMATGuruNY » Thu Oct 11, 2018 2:22 am
subh2273 wrote:For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ?

(1) R < S

(2) X > Y
Range = highest - lowest.
Thus:
Lowest = highest - range.

In Section 1, lowest = highest - range = X-R.
In Section 2, lowest = highest - range = Y-S.

If the lowest weight in Section 1 is greater than the lowest weight in Section 2, we get:
X-R > Y-S
X+S > Y+R.

Question rephrased: Is X+S > Y+R?

Statement 1: R < S
No information about X or Y.
INSUFFICIENT.

Statement 2: X > Y
No information about R or S.
INSUFFICIENT.

Statements combined:
Inequalities can be ADDED TOGETHER.
When we add, the < > must face the SAME DIRECTION in each inequality.
To match X > Y in statement 2, rephrase R < S in statement 1 as S > R.
Adding together X > Y and S > R, we get:
X+S > Y+R.
SUFFICIENT.

The correct answer is C.
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