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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## For the students in a Physical Fitness Class Section #1, the ##### This topic has 3 expert replies and 0 member replies ## For the students in a Physical Fitness Class Section #1, the ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ? (1) R < S (2) X > Y ### GMAT/MBA Expert GMAT Instructor Joined 09 Oct 2010 Posted: 1449 messages Followed by: 32 members Upvotes: 59 subh2273 wrote: For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ? (1) R < S (2) X > Y ${\text{range}} = {V_{\max }} - {V_{\min }}\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{V_{\min }} = {V_{\max }} - {\text{range}}$ Section 1: weights have minimum value (X-R) kg and maximum value X kg. Section 2: weights have minimum value (Y-S) kg and maximum Y kg. $X - R\,\,\,\mathop > \limits^? \,\,Y - S$ $\left( 1 \right)\,\,R < S\,\,\,\,\,\,\left\{ \begin{gathered} \,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {90,10,90,20} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{YES}}} \right\rangle \,\,\,\,\,\,\left( {80\,\,\mathop > \limits^? \,70} \right) \hfill \\ \,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {80,10,90,20} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{NO}}} \right\rangle \,\,\,\,\,\,\,\,\left( {70\,\,\mathop > \limits^? \,70} \right) \hfill \\ \end{gathered} \right.$ $\left( 2 \right)\,\,X > Y\,\,\,\,\,\left\{ \begin{gathered} \,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {90,10,80,10} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{YES}}} \right\rangle \,\,\,\,\,\,\left( {80\,\,\mathop > \limits^? \,70} \right) \hfill \\ \,{\text{Take}}\,\,\left( {X,R,Y,S} \right) = \,\left( {90,20,80,10} \right)\,\,\,\,\, \Rightarrow \,\,\,\,\left\langle {{\text{NO}}} \right\rangle \,\,\,\,\,\,\,\,\left( {70\,\,\mathop > \limits^? \,70} \right) \hfill \\ \end{gathered} \right.$ $\left( {1 + 2} \right)\,\,\,\,\left\{ \begin{gathered} \,\,R < S\,\,\, \Rightarrow \,\,\,\, - R > - S \hfill \\ \,\,X > Y \hfill \\ \end{gathered} \right.\,\,\,\,\,\,\,\,\mathop \Rightarrow \limits^{\left( + \right)} \,\,\,\,\,\,\,X + \left( { - R} \right)\,\, > \,\,Y + \left( { - S} \right)\,\,\,\,\, \Rightarrow \,\,\,\left\langle {{\text{YES}}} \right\rangle \,$ The correct answer is therefore (C). This solution follows the notations and rationale taught in the GMATH method. Regards, Fabio. _________________ Fabio Skilnik :: GMATH method creator ( Math for the GMAT) English-speakers :: https://www.gmath.net Portuguese-speakers :: https://www.gmath.com.br ### GMAT/MBA Expert GMAT Instructor Joined 22 Aug 2016 Posted: 1898 messages Followed by: 30 members Upvotes: 470 subh2273 wrote: For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ? (1) R < S (2) X > Y Given: â€¢ Section 1: Range = R; Highest weight = X, thus, Lowest weight = X - R â€¢ Section 2: Range = S; Highest weight = Y, thus, Lowest weight = Y - S Question: Is X - R > Y - S? Let's take each statement one by one. (1) R < S Case 1: If X > Y, then X - R > Y - S => X - Y > R - S => |X - Y| > -|R - S|, which is ALWAYS correct, irespective of values of X, Y, R, and S. Case 2: If X < Y, then X - R > Y - S => X - Y > R - S => -|X - Y| > -|R - S|, which is NOT necessarily correct since both |X - Y| and |R - S| are negative numbers, they cannot be compared untill we have their unique values. Insufficient. (2) X > Y As with Statement 1, same with Statement 2. Insufficient. (1) and (2) together Case 1 discussed in Statement 1 is applicable, thus, X - R > Y - S. The answer is Yes. Sufficient. The correct answer: C Hope this helps! -Jay _________________ Manhattan Review GMAT Prep Locations: New York | Bangalore | Guangzhou | Buenos Aires | and many more... Schedule your free consultation with an experienced GMAT Prep Advisor! Click here. ### GMAT/MBA Expert GMAT Instructor Joined 25 May 2010 Posted: 15257 messages Followed by: 1861 members Upvotes: 13060 GMAT Score: 790 subh2273 wrote: For the students in a Physical Fitness Class Section #1, the range of their weights is R kg and the highest amount of weight is X kg. For the students in Physical Fitness Class Section #2, the range of their weights is S kg and the highest amount of weight is Y kg. Is the lowest weight of the students in Section #1 greater than the lowest weight of the students in Section #2 ? (1) R < S (2) X > Y Range = highest - lowest. Thus: Lowest = highest - range. In Section 1, lowest = highest - range = X-R. In Section 2, lowest = highest - range = Y-S. If the lowest weight in Section 1 is greater than the lowest weight in Section 2, we get: X-R > Y-S X+S > Y+R. Question rephrased: Is X+S > Y+R? Statement 1: R < S No information about X or Y. INSUFFICIENT. Statement 2: X > Y No information about R or S. INSUFFICIENT. Statements combined: Inequalities can be ADDED TOGETHER. When we add, the < > must face the SAME DIRECTION in each inequality. To match X > Y in statement 2, rephrase R < S in statement 1 as S > R. Adding together X > Y and S > R, we get: X+S > Y+R. SUFFICIENT. The correct answer is C. _________________ Mitch Hunt Private Tutor for the GMAT and GRE GMATGuruNY@gmail.com If you find one of my posts helpful, please take a moment to click on the "UPVOTE" icon. Available for tutoring in NYC and long-distance. For more information, please email me at GMATGuruNY@gmail.com. Student Review #1 Student Review #2 Student Review #3 Free GMAT Practice Test How can you improve your test score if you don't know your baseline score? Take a free online practice exam. Get started on achieving your dream score today! 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