For all numbers x such that x does not equal 1, if g(x) is defined by g(x)= x^2+2 / x-1 , then (1/g(2))(1/2g(x)= ? A. 6(x-1) / x^2+2 B. 6(x^2+2)/x-1 C. x^2+2 / 2(x-1) D. x-1 / 6(x^2+2) E. x^2+2 / 6(x-1) Answer is D I have no idea how to get the answer.. please advise! Thanks so much

gmatpup wrote:For all numbers x such that x does not equal 1, if g(x) is defined by g(x)= x^2+2 / x-1 , then (1/g(2))(1/2g(x)= ? A. 6(x-1) / x^2+2 B. 6(x^2+2)/x-1 C. x^2+2 / 2(x-1) D. x-1 / 6(x^2+2) E. x^2+2 / 6(x-1) Answer is D I have no idea how to get the answer.. please advise! Thanks so much g(x)= (x² + 2)/(x - 1) g(2)= (2² + 2)/(2 - 1) = 6 (1/g(2))(1/2g(x)= [1/6] * [1/2 * (x² + 2)/(x - 1)] = (x - 1)/12(x² + 2), none of the options.

I made a huge error.. It should read: (1/g(2))(1/g(x)) = ?

gmatpup wrote:I made a huge error.. It should read: (1/g(2))(1/g(x)) = ? g(x)= (x² + 2)/(x - 1) g(2)= (2² + 2)/(2 - 1) = 6 (1/g(2))(1/g(x)= [1/6] * [(x² + 2)/(x - 1)] = (x - 1)/6(x² + 2) The correct answer is D.

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