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For a finite sequence of nonzero numbers...

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What is the number of variations in sign for the sequence 1,-3,2,5,-4,-6?

1
0
No votes
2
0
No votes
3
1
100%
4
0
No votes
5
0
No votes
 
Total votes: 1
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by ProGMAT » Mon Aug 12, 2013 6:48 am
For a finite sequence of nonzero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative.
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by Brent@GMATPrepNow » Mon Aug 12, 2013 6:57 am
ProGMAT wrote:For a finite sequence of non-zero numbers, the number of variations in sign is defined as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence {1, -3, 2, 5, -4, -6} ?
A. 1
B. 2
C. 3
D. 4
E. 5
We're asked to look at every pair of consecutive numbers. If the product of that pair is negative, this counts as one variation.

Let's examine the pairs of consecutive numbers:

1 and -3: product is negative
-3 and 2: product is negative
2 and 5: product is positive
5 and -4: product is negative
-4 and -6: product is positive

Since 3 pairs of consecutive numbers have negative products, the correct answer is C

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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