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Flannery is 28 years old and Harumi is 11 years old. In how many years will Flannery’s age be twice Harumi’s age?

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Flannery is 28 years old and Harumi is 11 years old. In how many years will Flannery’s age be twice Harumi’s age?

by Vincen » Mon May 18, 2020 7:02 am

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Flannery is 28 years old and Harumi is 11 years old. In how many years will Flannery’s age be twice Harumi’s age?

(A) 3
(B) 4
(C) 6
(D) 8
(E) 9

[spoiler]OA=C[/spoiler]

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Re: Flannery is 28 years old and Harumi is 11 years old. In how many years will Flannery’s age be twice Harumi’s age?

by Scott@TargetTestPrep » Sun May 24, 2020 4:58 am
Vincen wrote: ↑
Mon May 18, 2020 7:02 am
 Flannery is 28 years old and Harumi is 11 years old. In how many years will Flannery’s age be twice Harumi’s age?

(A) 3
(B) 4
(C) 6
(D) 8
(E) 9

[spoiler]OA=C[/spoiler]
Let x be the number of years from now so that Flannery’s age will be twice Harumi’s age. We can create the equation:

28 + x = 2(11 + x)

28 + x = 22 + 2x

6 = x

Answer: C

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