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mangomangodolly
- Junior | Next Rank: 30 Posts
- Posts: 13
- Joined: Sun Nov 25, 2012 1:30 am
Arrange the above in multiples of prime factors and their powersmangomangodolly wrote:Find the number of zero's at the end of the below number.
5*15*25*35*60*80*160
5
15=3*5
25=5^2
35=5*7
60=2^2*3*5
80=2^4*5
160=2^5*5
5*15*25*35*60*80*160 = 2^11 * 3^2 * 5^8 * 7
The number of zeroes at the end will be equal to power of 10 (2*5) this number contains.
2^8 * 5^8 will give (2*5)^8 i.e. 10^8
Hence, 8 zeroes at the end....
