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Stumbler

by mikeclarke44 » Sat Jun 09, 2007 2:05 pm
I have been struggling to figure out how this anwer is performed.

2^(4-1)^2
------------
2^3-2

Answers
a). 2^8
b). 2^7
c). 2^5
d). 2^3
e). 2^1

The correct anwer is (a), but I have no idea how they got there!!
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Re: Stumbler

by Neo2000 » Sat Jun 09, 2007 6:13 pm
mikeclarke44 wrote:I have been struggling to figure out how this anwer is performed.

2^(4-1)^2
------------
2^3-2
Simplify the powers first

So you get (4-1)^2 = 3^2 = 9 Therefore in the Numerator you get 2^9
Similarly in the Denominator you will get 2^1

Hence (2^9)/(2) = 2^8
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by mikeclarke44 » Sun Jun 10, 2007 1:22 pm
Wow, that was so easy I can't believe I didn't grasp it. Thanks
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Re: Stumbler

by mtr » Wed Nov 14, 2007 12:00 pm
Neo2000 wrote:
mikeclarke44 wrote:I have been struggling to figure out how this anwer is performed.

2^(4-1)^2
------------
2^3-2
So you get (4-1)^2 = 3^2 = 9 Therefore in the Numerator you get 2^9
I was under the impression that 2^(4-1)^2 did not equal 2^9. That 2^3^2 = 2^6 ???

Also shouldn't the denominator be 2^(3-2) rather than 2^3-2 ?
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Re: Stumbler

by gabriel » Fri Nov 16, 2007 2:10 am
mtr wrote:
Neo2000 wrote:
mikeclarke44 wrote:I have been struggling to figure out how this anwer is performed.

2^(4-1)^2
------------
2^3-2
So you get (4-1)^2 = 3^2 = 9 Therefore in the Numerator you get 2^9
I was under the impression that 2^(4-1)^2 did not equal 2^9. That 2^3^2 = 2^6 ???

Also shouldn't the denominator be 2^(3-2) rather than 2^3-2 ?
(2^3)^2= 2^(3*2)=2^6 ...

2^(3)^2 or 2^(3^2) = 2^9 ...

Regards
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