BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Filling the pool

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 12
Joined: Wed Aug 06, 2008 9:19 am
Thanked: 2 times
by cornell2005 » Mon Aug 11, 2008 5:45 pm
If Pool Y currently contains more water than Pool X, and if Pool X is currently filled to 2/7 of its capacity, what percent of the water currently in Pool Y needs to be transferred to Pool X if Pool X and Pool Y are to have equal volumes of water?

(1) If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity.

(2) Pool X has a capacity of 14,000 gallons.

Thanks in advance.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Data Sufficiency |
Junior | Next Rank: 30 Posts
Posts: 11
Joined: Wed Jun 25, 2008 5:30 am

by floravaze » Tue Aug 12, 2008 2:28 am
is the answe A?
let me explain why i think so.Firstly,i am assumimg that the two pools have equal capacity.
A s sufficient because we can deduce using the stem that what is added to pool A is 4/7 q'ty of water(6/7 -2/7) which is the quantity in pool Y and you can proceed from there.
B is not sufficient because it tells us nothing about what is found in Y.We only deduce that pool x needs 10000 more gallons of water.
so answer is A.
touch the sky
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Tue Aug 12, 2008 2:59 am
I don't think you need to assume the two pools have equal capacity.
We have
current amount in Y > 2/7X
"If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity."
Thanks to this sentence we can infer that the current amount in Y is 4/7X:
4/7X>2/7X
1/7 (+/- 14%) from pool Y has to be transferred to pool X

Agree with A
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 12
Joined: Wed Aug 06, 2008 9:19 am
Thanked: 2 times

by cornell2005 » Tue Aug 12, 2008 4:16 am
I would have chosen A as well. But I'm having trouble solving the last step. (you dont need to for DS, but I feel like I should be able to)

can you please explain how you get from 4/7x > 2/7x saying that 1/7 of Y must be added to X? Thanks.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Tue Aug 12, 2008 4:31 am
let's say X=1 (total possible capacity)
By one side you have Y with 4/7 and X with 2/7
you take 1/7 from Y and you put it to X
Therefore, you have 3/7 for each
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 12
Joined: Wed Aug 06, 2008 9:19 am
Thanked: 2 times

by cornell2005 » Tue Aug 12, 2008 11:02 am
ahh i see.. thanks. I got caught up on the fact that you dont know Y's capacity.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 42
Joined: Tue Jun 17, 2008 1:18 pm
Thanked: 2 times

by kshin78 » Tue Aug 12, 2008 2:21 pm
pepeprepa wrote:I don't think you need to assume the two pools have equal capacity.
We have
current amount in Y > 2/7X
"If all the water currently in Pool Y were transferred to Pool X, Pool X would be filled to 6/7 of its capacity."
Thanks to this sentence we can infer that the current amount in Y is 4/7X:
4/7X>2/7X
1/7 (+/- 14%) from pool Y has to be transferred to pool X

Agree with A
quick question. shouldn't the % be 1/7 of 4/7 which is same as 1/4, therefore 25% of the capacity? i agree w/ the answer but wanted to solve the prob...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1