If 14k = 42 and mk/50 = 42/100 = 21/50, then it will satisfy the given equation.Deepthi Subbu wrote:If 42.42 = k(14 + m/50), where k and m are positive integers and m < 50, then what is the value of
k + m ?
(A) 6
(B) 7
(C) 8
(D) 9
(E) 10
OA E
Unlike the substitution method , is there a shortcut to solve the problem ?
That´s right, Anshu!anshumishra wrote:If 14k = 42 and mk/50 = 42/100 = 21/50, then it will satisfy the given equation.
I used the same logic, and think that everything is ok with our solutiondjyogi wrote:We can also notice that if 42.42 is written as a 14k +mk/50, then mk/50 is a remainder, which equals to 42/100 (it is a remainder, because in general view m=nq (q is constant) + r, when m is divided by n and a remainder is r). then we solve for mk and can factor the mk value of 21 into primes, which yields only sum of 10.
please, tell me if that is legible approach? for me it is much easier than picking values for k.
Hi djyogi and LalaB!djyogi wrote:We can also notice that if 42.42 is written as a 14k +mk/50, then mk/50 is a remainder, which equals to 42/100 (it is a remainder, because in general view m=nq (q is constant) + r, when m is divided by n and a remainder is r)
My pleasure! Good studies and success in your GMAT!djyogi wrote:thank you fskilnik for explanation
