If n and k are positive integers, is n divisible by 6?
(1) n = k(k + 1)(k - 1)
(2) k – 1 is a multiple of 3.
(1) n = k(k + 1)(k - 1)
(2) k – 1 is a multiple of 3.
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A. From 1), n is the product of three consecutive integers: k-1, k and k+1. So n is divisible by 3! = 6. (the product of d consecutive integers is always divisible by d!). Statement 2) is clearly insufficient on its own.Mani_mba wrote:If n and k are positive integers, is n divisible by 6?
(1) n = k(k + 1)(k - 1)
(2) k – 1 is a multiple of 3.
You mixed the 1st statement with the 2nd. You should consider the 2nd statement seperately inorder to determine if it is sufficient or not. So, with thatBidisha800 wrote:I understand why stmt 1 is sufficient but do not understand how stmt 2 is NOT sufficient.
Probably I'm missing something so please help me out...
k-1 = 3m
k=3m+1
k+1 =3m+2
n=k(k+1)(k-1)
=3m(3m+1)(3m+2)
m=0 n=0 divisible by 6
m=1 n=3.4.5 divisible by 6
m=2 n=6.7.8 divisible by 6
m=3 n=9.10.11 divisible by 6
.....
so why (B) is CLEARLY insufficient by its own ?
so why the answer is (A) ?
THANKS ....Vemuri wrote:You mixed the 1st statement with the 2nd. You should consider the 2nd statement seperately inorder to determine if it is sufficient or not. So, with thatBidisha800 wrote:I understand why stmt 1 is sufficient but do not understand how stmt 2 is NOT sufficient.
Probably I'm missing something so please help me out...
k-1 = 3m
k=3m+1
k+1 =3m+2
n=k(k+1)(k-1)
=3m(3m+1)(3m+2)
m=0 n=0 divisible by 6
m=1 n=3.4.5 divisible by 6
m=2 n=6.7.8 divisible by 6
m=3 n=9.10.11 divisible by 6
.....
so why (B) is CLEARLY insufficient by its own ?
so why the answer is (A) ?
k-1 = 3m
k=3m+1
k+1 =3m+2
is not enough to answer the question if n is divisible by 6 or not.