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f (x) = x² – 3

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f (x) = x² – 3

by sanju09 » Fri Jul 23, 2010 2:43 am
If f (x) = x² - 3, where x is an integer, which of the following could be a value of f (x)?
I. 6
II. 0
III. -6
A. I only
B. I and II only
C. II and III only
D. I and III only
E. I, II and III

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by gmatmachoman » Fri Jul 23, 2010 2:50 am
A. I only

Explanation :

f(x) = x^2 -3

Let x=0 then f(x) = -3
X= 1 then f(x) = -2

So least value of f(x) is -3 when X is a integer.

f(x) will not become 0 at any value for x to be a integer.
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by selango » Fri Jul 23, 2010 3:15 am
f (x) = x² - 3

f(x)=6,

x² - 3=6,

x²=9,x=+3 or -3

Possible.

f(x)=6,

x² - 3=0,

x²=3,x=sqrt(3)

x is not an integer,Not possible

f(x)=-6,

x² - 3=-6,

x²=-3,square of integer cannot be -ve

Pick A
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by outreach » Fri Jul 23, 2010 3:22 am
A
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