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by jainrahul1985 » Tue Oct 18, 2011 10:39 pm
Recently Mary gave a birthday party for her daughter at which she served both chocolate and strawberry ice cream. There were 8 boys who had chocolate ice cream, and 9 girls who had strawberry. Everybody there had some ice cream, but nobody tried both. What is the mawimum possible number of girls who had some chocolate ice cream?
1) Exactly thirty children attended the party
2) Fewer than half the children had strawberry ice cream

OA A
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by shankar.ashwin » Tue Oct 18, 2011 10:51 pm
Chocolate (Boys) = 8
Strawberry (Girls) = 9

(1) Total Children = 30.
We already know (8+9=17) what these 17 children had.

For max possible girls who had chocolate, consider all the remaining children to be girls.
Therefore, Chocolate(Girls) = 30-17=13. Sufficient.

(2) Fewer than half had strawberry. The total could be anything, above 19. We cannot say exactly how many girls would have had chocolate ice-cream.
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by neelgandham » Wed Oct 19, 2011 2:12 am
1) Exactly thirty children attended the party

Boys who had chocolate icecream = 8
Girls who had strawberry icecream = 9
Total number of students = 30

If the remaining students are girls and if we can find how many they are, we can answer the question posed. i.e [spoiler]and yes we can.Maximum possible # of girls = 30-9-8 = 13[/spoiler]

Sufficient

2) Fewer than half the children had strawberry ice cream

9 < (1/2)*Total number of students => 9 < (1/2)*(x+9+8) => x can be any number greater than 1

Insufficient - Option A
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