BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Exponents - Quick Question

Expert replies
by cgiles01 » Thu Jul 05, 2007 9:21 am
I had trouble with the following question from GMAT Prep Test 2:

What is the greatest prime factor of 4^17 - 2^28?

There is probably a very simple way of solving this problem. Any assistance is greatly appreciated!

(Answer is 7)

Chris
Giles
Join the discussion
Source: — Problem Solving |

by givemeanid » Thu Jul 05, 2007 9:42 am
4^17 - 2^28
= (2^2)^17 - 2^28
= 2^34 - 2^28 -> From the rule (x^y)^z = x^(yz)
= 2^28(2^6 - 1) -> From the rule x^(r+s) = x^r * x^s
= 2^28 * 63
= 2^28 * 3 * 3 * 7


Answer is 7.
So It Goes
Join the discussion

by cgiles01 » Thu Jul 05, 2007 9:53 am
I can get to 2^34 - 2^28, but still a little lost how you got to 2^28(2^6 - 1)

Thanks for your help
Giles
Join the discussion

by givemeanid » Thu Jul 05, 2007 10:05 am
cgiles01 wrote:I can get to 2^34 - 2^28, but still a little lost how you got to 2^28(2^6 - 1)

Thanks for your help
2^34 = 2^(28+6) = 2^28 * 2^6
This is from the rule of exponents: x^(r+s) = x^r * x^s. In this case, x = 2, r = 28, s = 6
So It Goes
Join the discussion

by cgiles01 » Thu Jul 05, 2007 10:12 am
...and the -1 comes from factoring out the 2^28. Got it! Your awesome!

Chris
Giles
Join the discussion

another clarification pls,

by gmat_2007 » Fri Jul 20, 2007 4:47 pm
how does 2^28 * 3 * 3* 7 equal 7??
Join the discussion

Re: another clarification pls,

by givemeanid » Fri Jul 20, 2007 5:42 pm
gmat_2007 wrote:how does 2^28 * 3 * 3* 7 equal 7??
The question is asking for the greatest prime factor. After factoring, you can see 7 fits the bill. Hence, the answer is 7.
So It Goes
Join the discussion

by gmat_2007 » Thu Jul 26, 2007 2:02 pm
Thanks for the reply. I was in a mental funk when I asked that questions!
Join the discussion