Seems type what is less than 5k,
seeing the options :
(1) 4^(x+1) > 16,000
(2) 4^(x+1) > 4^(x) + 12,288
1=> 4^x*4 > 16k => x^4>4K => x>8
2=> 4^x*4 > 4^x + 12888 =? 3*4^x > 12888 => 4^x > 4296
if u put whole q, we can deduce further
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exponents problem
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The second statement is 4^x > 4096
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The correct version of the question appears above.Is 4^x less than 5000?
1) 4^(x+1) > 16,000
2) 4^(x+1) = 4^x + 12,288
Statement 1: 4^(x+1) > 16,000
4^x * 4 > 16,000
4^x > 4000.
Since 4^x = 4001 and 4^x = 5001 both satisfy statement 1, insufficient.
Statement 2: 4^(x+1) = 4^x + 12,288
Since statement 2 gives us an equation (as opposed to an inequality), we can solve for the value of 4^x (and for the value of x).
Sufficient.
The correct answer is B.
Here's the math behind statement 2:
4^(x+1) = 4^x + 12,288
4^(x+1) - 4^x = 12,288
(4^x * 4) - 4^x = 12,288
4^x * (4-1) = 12,288
4^x = 4096
(since 4096 = 4^6, x=6).
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
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As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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