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by akahuja143 » Sat Apr 03, 2010 8:14 pm
Is x > y?

(1) Sqrt(x)> y

(2) x^3 > y


OA C Please explain your answers if you any method other than plugging numbers

Thanks

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Last edited by akahuja143 on Sat Apr 03, 2010 8:36 pm, edited 1 time in total.
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Source: — Data Sufficiency |
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by thephoenix » Sat Apr 03, 2010 8:31 pm
akahuja143 wrote:Is x > y?

(1) > y

(2) x^3 > y


OA C Please explain your answers if you any method other than plugging numbers

Thanks

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s1 is incomplete
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by student22 » Sat Apr 03, 2010 8:32 pm
Can you fix statement 1 please. What's "> y"?
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by akahuja143 » Sat Apr 03, 2010 8:36 pm
Sorry guys fixed it
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by student22 » Sat Apr 03, 2010 8:45 pm
Are you sure it's not A?

sqrt(x) > y ---> square both sides to get x > y^2. Sufficient to deduce that x > y, regardless if y is positive or negative.
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by akahuja143 » Sat Apr 03, 2010 9:06 pm
yeah for instance because we dunno know whether x and Y are fractions or integers

for instance
X=4, sqrt(x) =2 y =1
x =1/4 sqrt(y) =1/2 y =1/3
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by thephoenix » Sat Apr 03, 2010 9:22 pm
https://www.beatthegmat.com/posting.php? ... ly&t=55563
solved here
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by eaakbari » Sat Apr 03, 2010 11:01 pm
I think plugging numbers is the fastest and easiest method. You just have to remember to substitute with "weird number " also that being fractions, negative numbers, 0 and 1.

Youve posted the wrong link phoenix. Do check
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