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Source: — Data Sufficiency |
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by netigen » Mon Jun 02, 2008 1:55 pm
Ans is D

solve the first eq by separating out y in the denominator

in B the pq will cut out each other and you are left with x/y
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by molt_llest » Tue Jun 03, 2008 3:00 am
I don't get to separate y in the denominator. Could you do the steps you took?
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by zacharyz » Tue Jun 03, 2008 5:17 am
For Statement 1:

2/3 = x(x+3) / (xy+3y)

So let's look at just the denominator:
xy + 3y

Factor y out of this to be:
y*(x+3)

Now, you should be able to see that the numerator is:
x*(x+3)
and the denominator is:
y*(x+3)

The (x+3) cancels out, so the right part of that equation is simply:
x/y

Now, you know that:
2/3 = x/y

and that is good.

Note - this is only good for x does not equal -3 since that would make the denominator 0.

Statement 2
-------------
As netigen points out, the p/q cancels out on both sides, resulting in:
2/3 = x/y

So both are sufficient ( D )
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by molt_llest » Tue Jun 03, 2008 5:25 am
now!! It was pretty easy but I didn't see it...

Thank you!!!
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