Equations
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- Senior | Next Rank: 100 Posts
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For Statement 1:
2/3 = x(x+3) / (xy+3y)
So let's look at just the denominator:
xy + 3y
Factor y out of this to be:
y*(x+3)
Now, you should be able to see that the numerator is:
x*(x+3)
and the denominator is:
y*(x+3)
The (x+3) cancels out, so the right part of that equation is simply:
x/y
Now, you know that:
2/3 = x/y
and that is good.
Note - this is only good for x does not equal -3 since that would make the denominator 0.
Statement 2
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As netigen points out, the p/q cancels out on both sides, resulting in:
2/3 = x/y
So both are sufficient ( D )
2/3 = x(x+3) / (xy+3y)
So let's look at just the denominator:
xy + 3y
Factor y out of this to be:
y*(x+3)
Now, you should be able to see that the numerator is:
x*(x+3)
and the denominator is:
y*(x+3)
The (x+3) cancels out, so the right part of that equation is simply:
x/y
Now, you know that:
2/3 = x/y
and that is good.
Note - this is only good for x does not equal -3 since that would make the denominator 0.
Statement 2
-------------
As netigen points out, the p/q cancels out on both sides, resulting in:
2/3 = x/y
So both are sufficient ( D )
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- Senior | Next Rank: 100 Posts
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