Bhupisuhag wrote:If x and y are integers such that x < y < 0, what is x - y?
(1) (x + y)(x - y) = 5
(2) xy = 6

Target question: What is x - y?

Statement 1: (x + y)(x - y) = 5
First, if x and y are integers, then x+y and x-y are both integers.
Second, if x < y < 0, then x+y is negative and x-y is negative.
Third, (x + y)(x - y) = 5, then there are only 2 cases:
case 1: (x+y) = -1 and (x-y) = -5
case 2: (x+y) = -5 and (x-y) = -1

Case 1 is impossible. If x and y are 2 different negative integers, then (x+y) cannot equal -1.
So, if case 1 is not possible, then case 2 must be true. This means that it must be the case that x+y= -5 and x-y= -1
So, statement 1 is sufficient.

Statement 2: xy = 6
If xy=6 (and x<y<0), there are two cases to consider
case 1: x = -3 & y = -2, in which case x-y = -1
case 2: x = -6 & y = -1, in which case x-y = -5
Since we get two conflicting answers to the target question, statement 2 is not sufficient.

Answer = A

Cheers,
Brent