perimeter of the shaded region

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perimeter of the shaded region

by jain2016 » Tue Apr 19, 2016 8:58 am
In the figure to the right, circle O has center O, diameter AB and a radius of 5. Line CD is parallel to the diameter. What is the perimeter of the shaded region?

A) (5/3)pie + 5 under root 3

B) (5/3)pie + 10 under root 3

C) (10/3)pie + 5 under root 3

D) (10/3)pie + 10 under root 3

E) (10/3)pie + 20 under root 3

OAD

Hi Experts ,

Please explain.

Many thanks in advance.

SJ
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by Ides_of_marzo » Tue Apr 19, 2016 9:19 am
Do you mean root 3 or root 2?

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by Brent@GMATPrepNow » Tue Apr 19, 2016 9:19 am
In the figure to the right, circle O has center O, diameter AB and a radius of 5. Line CD is parallel to the diameter. What is the perimeter of the shaded region?

A. (5/3)pi + 5√3
B. (5/3)pi + 10√3
C. (10/3)pi + 5√3
D. (10/3)pi + 10√3
E. (10/3)pi + 20√3

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IMPORTANT: unless stated otherwise, the diagrams in Problem Solving geometry questions are DRAWN TO SCALE.
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I'll solve this question using estimation.
Since the diameter AB = 10, we can ESTIMATE the length of CB.
It looks like CB is just a little bit shorter than AB.
So, I'll say that the length of side CB is approximately 9.
This means the length of side EB is approximately 9 as well.
Finally, arc EC looks a little bit shorter than sides CB and EB, so I'll estimate it to be length 8

So, the TOTAL perimeter = 9 + 9 + 8 = 26

Now check the answer choices:

ASIDE: On test day, everyone should know the following apprximations:
√2 ≈ 1.4
√3 ≈ 1.7
√5 ≈ 2.2
Also, we'll say that pi ≈ 3


A. (5/3)pi + 5√3 ≈ 5 + 8.5 ≈ 13.5
B. (5/3)pi + 10√3 ≈ 5 + 17 ≈ 22
C. (10/3)pi + 5√3 ≈ 10 + 8.5 ≈ 18.5
D. (10/3)pi + 10√3 ≈ 10 + 17 ≈ 27
E. (10/3)pi + 20√3 ≈ 10 + 34 ≈ 44

Of these, it appears that D is the closest.

Aside: We can see that answer choice B is pretty close too. At this point, you have a time-management decision. You can either stick with D, and use your extra time elsewhere, or your can spend time trying to be more certain of the answer. Your choice.

That said, D is the correct answer.

Cheers,
Brent
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by OptimusPrep » Tue Apr 19, 2016 8:27 pm
jain2016 wrote:In the figure to the right, circle O has center O, diameter AB and a radius of 5. Line CD is parallel to the diameter. What is the perimeter of the shaded region?

A) (5/3)pie + 5 under root 3

B) (5/3)pie + 10 under root 3

C) (10/3)pie + 5 under root 3

D) (10/3)pie + 10 under root 3

E) (10/3)pie + 20 under root 3

OAD

Hi Experts ,

Please explain.

Many thanks in advance.

SJ
Let us first find the angles related to the perimeter
Since CD is parallel yo AB, therefore angle CBA = 30 and angle CBE = 60
Now from the property of the circle, angle at centre is twice the angle at circumference
angle COE = 2*angle CBE
Therefore angle COE = 120

Now let us try and find the lengths.
arc CAE = 1/3 (2*pi*5) {Since 120 = 360/3}
arc CAE = (10/3)*pi

Now coming to the sides,
Draw a line from C to O.
In the triangle COB, we have CO = OB = 5 (radius of the circle)
If we drop a perpendicular from OP on CB, we will have triangles OPB and OPC and PB = PC

In triangle OPB, we know that OB = 5
angle OBP = 30, angle OPB = 90
Cos 30 = PB/OB
√3/2 = PB/5
Therefore PB = 5√3/2

Hence CB = PB + PC = 5√3

Therefore the total parameter = arc CAE + CB + EB = 2*(5√3) + (10/3)*pi = (10/3)*pi + 10√3

Correct Option: D
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Screen Shot 2016-04-20 at 9.57.52 am.png