• Magoosh
Study with Magoosh GMAT prep

Available with Beat the GMAT members only code

• 5 Day FREE Trial
Study Smarter, Not Harder

Available with Beat the GMAT members only code

• Free Trial & Practice Exam
BEAT THE GMAT EXCLUSIVE

Available with Beat the GMAT members only code

• Free Veritas GMAT Class
Experience Lesson 1 Live Free

Available with Beat the GMAT members only code

• 1 Hour Free
BEAT THE GMAT EXCLUSIVE

Available with Beat the GMAT members only code

• 5-Day Free Trial
5-day free, full-access trial TTP Quant

Available with Beat the GMAT members only code

• Free Practice Test & Review
How would you score if you took the GMAT

Available with Beat the GMAT members only code

• Get 300+ Practice Questions

Available with Beat the GMAT members only code

• Award-winning private GMAT tutoring
Register now and save up to $200 Available with Beat the GMAT members only code • FREE GMAT Exam Know how you'd score today for$0

Available with Beat the GMAT members only code

## easy question NO2 from disclosure

This topic has 4 member replies
magical cook Master | Next Rank: 500 Posts
Joined
30 Jul 2006
Posted:
484 messages
Followed by:
1 members
2

#### easy question NO2 from disclosure

Tue Sep 26, 2006 7:34 am
Could anyone please give me some example to understand this question?? I am confused..

Which of the following procedures is alwasys equivalent to adding 5 numbers and then deviding the sum by 5?

I. Multiplying the 5 numbers and then finding the 5th root of the product.

II. Adding the 5 numbers, doubling the sum, and then moving the decimal point one place to the left.

III. Ordering the 5 numbers numerically and then selecting the middle number.

A) None
B) I only
C) II only
D) III only
E) I and III

cooldude Master | Next Rank: 500 Posts
Joined
09 Jul 2006
Posted:
108 messages
1
Tue Sep 26, 2006 8:41 am
method 1 - suppose we have numbers 4 8 9 27 1;so fifth root of product is 6

but adding them all then divide by 5 is not equal to 6

method 2-suppose a b c d e are any 5 inteers so sum is a+ b+ c+ d +e
and doubling it is 2(a+ b+ c+ d +e) the divide by 10 is {a+ b+ c+ d +e}/5

method 3-
again take 4 8 9 27 1 so middle no. is 8

hence u c only second is correct

magical cook Master | Next Rank: 500 Posts
Joined
30 Jul 2006
Posted:
484 messages
Followed by:
1 members
2
Tue Sep 26, 2006 7:45 pm
Thank you so much for your help.

it becomes very clear but one part... (sorry very basic)

as for the method 1
the product of the example 5 numbers: 4 8 9 27 1 will be 7776, and how come 5th root of 7776 is 6??

Thank you...

cooldude Master | Next Rank: 500 Posts
Joined
09 Jul 2006
Posted:
108 messages
1
Tue Sep 26, 2006 9:04 pm
break them into factors and make sets of 5 !!!!!!!

there r 5 2s and 5 3s

magical cook Master | Next Rank: 500 Posts
Joined
30 Jul 2006
Posted:
484 messages
Followed by:
1 members
2
Tue Sep 26, 2006 9:23 pm
Thank you again Cooddue...

I thought 5th root of product is like this (see attached), but actually that means "make 5 sets of factors"

Yes, there are 22222 and 33333.

Thank you!
Attachments

### Top First Responders*

1 GMATGuruNY 71 first replies
2 Rich.C@EMPOWERgma... 48 first replies
3 Brent@GMATPrepNow 37 first replies
4 Jay@ManhattanReview 26 first replies
5 ErikaPrepScholar 10 first replies
* Only counts replies to topics started in last 30 days
See More Top Beat The GMAT Members

### Most Active Experts

1 GMATGuruNY

The Princeton Review Teacher

129 posts
2 Rich.C@EMPOWERgma...

EMPOWERgmat

116 posts
3 Jeff@TargetTestPrep

Target Test Prep

106 posts
4 Max@Math Revolution

Math Revolution

92 posts
5 Scott@TargetTestPrep

Target Test Prep

92 posts
See More Top Beat The GMAT Experts