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Easy BUT!!!! OG 12 problem!

This topic has 1 expert reply and 1 member reply
soniadiana2011 Junior | Next Rank: 30 Posts Default Avatar
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Posted:
14 messages

Easy BUT!!!! OG 12 problem!

Post Thu May 31, 2012 10:26 am
A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100

Please explain me the answer!

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aneesh.kg Master | Next Rank: 500 Posts
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Post Thu May 31, 2012 11:04 am
soniadiana2011 wrote:
A carpenter constructed a rectangular sandbox with a
capacity of 10 cubic feet. If the carpenter were to
make a similar sandbox twice as long, twice as wide,
and twice as high as the fi rst sandbox, what would be
the capacity, in cubic feet, of the second sandbox?
(A) 20
(B) 40
(C) 60
(D) 80
(E) 100

Please explain me the answer!
If the edges of the initial box are a, b and c long, then
Volume = (a)(b)(c) = 10

If each of the dimensions is made twice, then the new lengths of the edges are 2a, 2b and 2c.
New Volume = (2a)(2b)(2c) = 8abc
Since abc = 10,
New Volume = 8*10 = 80 cubic feet

(D) is the answer.

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Aneesh Bangia
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aneesh.bangia@gmail.com

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GMAT/MBA Expert

Anurag@Gurome GMAT Instructor
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Post Thu May 31, 2012 11:01 am
soniadiana2011 wrote:
A carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide, and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?
Say, the first sandbox is a feet long, b feet wide, and c feet high.
Hence, volume of the first sandbox = abc = 10 cubic feet

Now, the second sandbox is 2a feet long, 2b feet wide, and 2c feet high.
Hence, volume of the second sandbox = (2a)*(2b)*(2c) = 8abc = 8*10 cubic feet = 80 cubic feet

The correct answer is D.

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Gurome, Inc.
1-800-566-4043 (USA)

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