Each term in the sequence A1 +A2 + A3 ----- + An is either 7 or 77 and th sum equals 350. What could be the value of n.
a) 38
b) 39
c) 40
d) 41
e) 42
a) 38
b) 39
c) 40
d) 41
e) 42
Let's take the simplest possible scenario. Imagine that every term in the sequence were 7. How many of those would we need for the sum to be 350? We'd need 50. Not an answer choice, but it is in the ballpark.Each term in the sequence A1 +A2 + A3 ----- + An is either 7 or 77 and th sum equals 350. What could be the value of n.
a) 38
b) 39
c) 40
d) 41
e) 42
Say, then that we had one 77. We'd need the 7's to sum to 273. (350 - 77 = 273) There are thirty-nine 7's in 273. If we have one 77 and and thirty-nine 7's, we'll have a total of 1 + 39 = 40 terms. Answer is C
