I think your question may have been

(1) x = (-3y+3)/(1-y) OR (1) x = (3y-3)/(1-y)

If it is so answer is C


If not IMO E

s1)--->x=3(y+1)/(y-1) x varies wrt y..insuff

s2)---->insuff

E

gmatmachoman wrote:Is x = 3?

(1) x =( −3y − 3)/(1− y)

(2)|x|/ x + x *| x| > 0

E

Had the question been

(1) x =( −3y + 3)/(1− y)

(2)|x|/ x + x *| x| > 0

Then C

Hi Guys, could you help me understand why the answer is C. I thought A was sufficient.

if it was (1) x = (-3y+3)/(1-y) then x = 3(1-y)/(1-y)...I was thinking we could strike off (1-y) then x=3 right?

or I should abandon this in DS cos y could be 1 and render x to be 0? is this the thinking?

also, st2 means that x should be positive so that expression in st2 > 0. is this right or wrong?

dxgamez wrote:Hi Guys, could you help me understand why the answer is C. I thought A was sufficient.

if it was (1) x = (-3y+3)/(1-y) then x = 3(1-y)/(1-y)...I was thinking we could strike off (1-y) then x=3 right?

or I should abandon this in DS cos y could be 1 and render x to be 0? is this the thinking?

also, st2 means that x should be positive so that expression in st2 > 0. is this right or wrong?

You asked the question and answered it too.

Exactly what your thinking, we cant strike it off as we do not know if its a non zero term, but statement two tells us that x>0 that is it is a non zero term and positive , then C becomes sufficient

@eaakbari

thanks a lot! now I know how I should think. still far away from how fantastic you guys think though, but working on it..

ajith wrote: ......................E

Had the question been

(1) x =( −3y + 3)/(1− y)

(2)|x|/ x + x *| x| > 0

Then C

Could you please check this ?
IMHO A