DS Question

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DS Question

by vinay1983 » Wed Sep 04, 2013 5:14 am
If p is a positive number, what is the value of p?

1. Modulus p-2 = 1 (I hope one can imagine the modulus around p-2)
2. p^2=4p-3
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by melguy » Wed Sep 04, 2013 5:43 am
Statement 1

|p-2|= 1

So p-2 = 1 (i.e. p = +3)
or p-2 = -1 (i.e. p = +1)

Not Sufficient

Statement 2

p^2 = 4p - 3
p^2 - 4p + 3 = 0
(p-3) (p-1) = 0
p = + 3 or p = +1

Not Sufficient

Combine

p = +3 and + 1 is the common value in both statements.

Answer should be E

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by vinay1983 » Wed Sep 04, 2013 7:53 am
melguy wrote:Statement 1

|p-2|= 1

So p-2 = 1 (i.e. p = +3)
or p-2 = -1 (i.e. p = +1)

Not Sufficient

Statement 2

p^2 = 4p - 3
p^2 - 4p + 3 = 0
(p-3) (p-1) = 0
p = + 3 or p = +1

Not Sufficient

Combine

p = +3 and + 1 is the common value in both statements.

Answer should be E
Correct!
You can, for example never foretell what any one man will do, but you can say with precision what an average number will be up to!