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DS question

Expert replies
by hemant_rajput » Sun May 05, 2013 7:30 am
77. What is the value of x^2 + y^2 ?
(1) x^2 + y^2 = 2xy + 1
(2) x^2 + y^2 = 4 - 2xy
[spoiler]
OA:E[/spoiler]
Source: Jeff Seckman
I'm no expert, just trying to work on my skills. If I've made any mistakes please bear with me.
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Source: — Data Sufficiency |

by srcc25anu » Sun May 05, 2013 7:53 am
IMO it should be C

ST1: x^2 + y^2 = 2xy + 1
we cannot find 3 variables from 1 eqaution
Hence Insufficient

St2: x^2 + y^2 = 4 - 2xy
we cannot find 3 variables from 1 eqaution
Hence Insufficient

Together: Adding the 2 equations we get 2(x^2 + y^2) = 1 + 4 (xy terms cancel out)
Hence x^2 + y^2 = 5/2
Hence Sufficient
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by hemant_rajput » Sun May 05, 2013 8:21 pm
srcc25anu wrote:IMO it should be C

ST1: x^2 + y^2 = 2xy + 1
we cannot find 3 variables from 1 equation
Hence Insufficient

St2: x^2 + y^2 = 4 - 2xy
we cannot find 3 variables from 1 equation
Hence Insufficient

Together: Adding the 2 equations we get 2(x^2 + y^2) = 1 + 4 (xy terms cancel out)
Hence x^2 + y^2 = 5/2
Hence Sufficient
Here is my approach

1 and 2 are definitely not sufficient alone.

now from 1 and 2 :-

2xy + 1 = 4 - 2xy
4xy = 3
xy = 3/4

now substituting value of xy in 1 and 2


1 x^2 + y^2 = 2 * 3/4 + 1 = 5/2

2 x^2 + y^2 = 4 - 2 * 3/4 = 4 - 3/2 = 5/2


I guess OA is wrong unless someone has some other method to prove OA is right.
I'm no expert, just trying to work on my skills. If I've made any mistakes please bear with me.
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by Blue_Skies » Tue May 07, 2013 12:00 pm
77. What is the value of x^2 + y^2 ?
(1) x^2 + y^2 = 2xy + 1
(2) x^2 + y^2 = 4 - 2xy

I think the answer is correct.

From 1) (x-y)^2 = 1 So x-y = plus minus 1. Their can be many solutions:
Just for +1 : (1,0)(2,1),(3,2).....(a,a-1)
Similiarly for -1 : their can be infinite solns.

From 2)
(x+y) ^ 2 = plus minus 2.
If you think about it every set of the form (2,0),...(a,a-2) will satisfy this for plus 2. Similarly for -2.

Even if you combine the results of 1 and 2 . You don't get anything because their is no overlap. Hence E is the answer.
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by GMATGuruNY » Tue May 07, 2013 12:42 pm
hemant_rajput wrote:77. What is the value of x^2 + y^2 ?
(1) x^2 + y^2 = 2xy + 1
(2) x^2 + y^2 = 4 - 2xy
Statement 1:
x² - 2xy + y² = 1.
(x-y)² = 1.
Thus, x-y = 1 or x-y = -1.
No way to determine the value of x² + y².
INSUFFICIENT.

Statement 2:
x² + 2xy + y² = 4.
(x+y)² = 4.
Thus, x+y = 2 or x+y = -2.
No way to determine the value of x² + y².
INSUFFICIENT.

Statements combined:
Adding x² - 2xy + y² = 1 to x² + 2xy + y² = 4, we get:
(x² - 2xy + y²) + (x² + 2xy + y²) = 1+4
2x² + 2y² = 5
x² + y² = 5/2.
SUFFICIENT.

The correct answer is C.
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by iamniladri » Wed May 08, 2013 4:56 am
I do agree with you but hemant_rajput says OA is E
Thanks
GMATGuruNY wrote:
hemant_rajput wrote:77. What is the value of x^2 + y^2 ?
(1) x^2 + y^2 = 2xy + 1
(2) x^2 + y^2 = 4 - 2xy
Statement 1:
x² - 2xy + y² = 1.
(x-y)² = 1.
Thus, x-y = 1 or x-y = -1.
No way to determine the value of x² + y².
INSUFFICIENT.

Statement 2:
x² + 2xy + y² = 4.
(x+y)² = 4.
Thus, x+y = 2 or x+y = -2.
No way to determine the value of x² + y².
INSUFFICIENT.

Statements combined:
Adding x² - 2xy + y² = 1 to x² + 2xy + y² = 4, we get:
(x² - 2xy + y²) + (x² + 2xy + y²) = 1+4
2x² + 2y² = 5
x² + y² = 5/2.
SUFFICIENT.

The correct answer is C.
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by GMATGuruNY » Wed May 08, 2013 5:30 am
iamniladri wrote:I do agree with you but hemant_rajput says OA is E
Thanks
The OA is incorrect.
The correct answer is C.

The two statements combined imply the following cases:
Case 1: x-y = 1 and x+y = 2
Here, x=3/2 and y=1/2, with the result that x² + y² = 5/2.

Case 2: x-y = 1 and x+y = -2
Here, x=-1/2 and y=-3/2, with the result that x² + y² = 5/2.

Case 3: x-y = -1 and x+y = 2
Here, x=1/2 and y=3/2, with the result that x² + y² = 5/2.

Case 4: x-y = -1 and x+y = -2
Here, x=-3/2 and y=-1/2, with the result that x² + y² = 5/2.

In each case, x² + y² = 5/2.
SUFFICIENT.

The correct answer is C.
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