If n = 9, then n - 2 = 7(prime) and sqroot(n)=3 (Prime)(1) n - 2 is a prime number.
If n = 7, then n - 2 = 5(prime) and sqroot(n)= Non-Integer (Non Prime)
Two different answers, hence Insufficient!
Assuming n2 = n^2,(2) n^2 is not a prime number.
n^2 is never a prime number, and satisfies all the real numbers on the number line.
So again considering two numbers on the number line.
If n = 9, then n - 2 = 7(prime) and sqroot(n)=3 (Prime)
If n = 7, then n - 2 = 5(prime) and sqroot(n)= Non-Integer (Non Prime)
Two different answers, hence Insufficient!
IMO E
Let me know if you are looking for a different approach!
